CODEWITHSUNDEEP
java
user569125
user569125

Reputation: 1463

String format using java

I have to make below statement as string.i am trying,but it's giving invalid character sequence.I know it is basic,But not able to do this.any help on this appreciated.

String str="_1";

'\str%' ESCAPE '\'

Output should be: '\_1%' ESCAPE '\'.

Thanks,

Chaitu

Upvotes: 0

Views: 3532

Answers (4)

Goblin Alchemist
Goblin Alchemist

Reputation: 827

String str="_1";
String source = "'\\str%' ESCAPE '\\'";
String result = source.replaceAll("str", str);

Another way to implement string interpolation. The replaceAll function finds all occurrences of str in the source string and replaces them by the passed argument.

To encode the backslash \ in a Java string, you have to duplicate it, because a single backslash works as an escape character.

Beware that the first argument if replaceAll is actually a regular expression, so some characters have a special meaning, but for simple words it will work as expected.

Upvotes: 1

rahulmohan
rahulmohan

Reputation: 1345

String str="_1";
String output = String.format("'\\%s%%' ESCAPE '\\'",str);
System.out.println(output);//prints '\_1%' ESCAPE '\'

Upvotes: 0

Flash
Flash

Reputation: 16703

Inside a string, a backslash character will "escape" the character after it - which causes that character to be treated differently.

Since \ has this special meaning, if you actually want the \ character itself in the string, you need to put \\. The first backslash escapes the second, causing it to be treated as a literal \ inside the string.

Knowing this, you should be able to construct the resulting string you need. Hope this helps.

Upvotes: 1

nfechner
nfechner

Reputation: 17525

String result = "'\\" + str + "%' ESCAPE '\\'";

Upvotes: 1

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