CODEWITHSUNDEEP
arraysmatlab4d
David Cole
David Cole

Reputation: 43

Indexing a 4D array with a 2D matrix of indicies

I currently have a 4D matrix of images in the form height x width x RGB x imageNumber in which I would like to index with a 2D array without using a for loop. The 2D array is in the format of height x width with the values being the image number to index.

I've got it working with A for loop but due to speed is there a way to do it without looping? I've tried resizing the matrix and index array but no luck so far.

Here is the for loop I've got working (albeit slowly on large images):

for height = 1:h
    for width = 1:w
        imageIndex = index(height, width);
        imageOutput(height, width, :) = matrix4D(height, width, :, imageIndex);
    end
end

where h and w are the height and width dimensions of the images.

Thank you!

Upvotes: 3

Views: 366

Answers (1)

Luis Mendo
Luis Mendo

Reputation: 112749

This uses implicit expansion to build a linear index that produces the desired result:

matrix4D = rand(4,2,3,5); % example matrix
[h, w, c, n] = size(matrix4D); % sizes
index = randi(n,h,w); % example index
ind = reshape(1:h*w,h,w) + reshape((0:c-1)*h*w,1,1,[]) + (index-1)*h*w*c; % linear index
imageOutput = matrix4D(ind); % desired result

For Matlab versions before R2016b you need to use bsxfun instead of implicit expansion:

ind = bsxfun(@plus, bsxfun(@plus, ...
    reshape(1:h*w,h,w), reshape((0:c-1)*h*w,1,1,[])), (index-1)*h*w*c); % linear index

Upvotes: 4

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