Reputation: 33
I'm trying to send a mail with an html attachment which contains a table from a Pandas dataframe and some plotted images in Python 3.7. When the data in the provided dataframe is not null and therefore there are plotted images to send, i wont run into the error. I also collect occuring errors in a list and add them to the final string which i want to sent with the mail.
def mailMe():
# Create the container email message.
msg = EmailMessage()
msg['Subject'] = 'Mail'
msg['From'] = sender
msg['To'] = receiver
#style overview table
htmlTable = (
df.style
.set_table_styles(styles)
.applymap(color_negative_red)
.set_caption('Auswertung')
.render()
)
#attach 100 dpi images
if not len(pngfiles100)==0:
for file in pngfiles100:
try:
with open(r'.\\temp\\'+file, 'rb') as fp:
img_data = fp.read()
msg.add_attachment(img_data, maintype='image',
subtype=imghdr.what(None, img_data),
filename=file)
except:
continue
fp.close()
#Error messages
htmlTable+='\n'+'<p style="font-family:Arial;"><b>Errors:</b></p>'
if not len(errors)==0:
for i in errors:
htmlTable+='\n'+'<p style="font-family:Arial;">'+i+'</p>'
pngFolder=r'.\\temp\\'
htmlTable+="""
<table>
<tbody>
"""
i=0
for col in df.columns:
tempDf=pd.DataFrame(data=df[col])
tmpHtml = (
tempDf.style
.set_table_styles(styles)
.applymap(color_negative_red)
.render()
)
if not len(pngfiles50)==0:
#embed 50 dpi images in mail
htmlTable+=u'\n'+'<tr><td>'+tmpHtml+'</td>'+'<td><img src="cid:image'+str(i+1)+'"></td></tr>'+u'\n'
try:
fp=open(pngFolder+pngfiles50[i],'rb')
msgImage = MIMEImage(fp.read())
fp.close()
msgImage.add_header('Content-ID','<image'+str(i+1)+'>')
msg.attach(msgImage)
except:
continue
i+=1
htmlTable+="""
</tbody>
</table>
"""
# Send the email via our own SMTP server.
with smtplib.SMTP(host) as s:
htmlTable = MIMEText(htmlTable,"html")
msg.attach(htmlTable)
s.send_message(msg)
Traceback:
Traceback (most recent call last):
File "c:\Users\mmai\.vscode\extensions\ms-python.python-2019.8.30787\pythonFiles\ptvsd_launcher.py", line 43, in <module>
main(ptvsdArgs)
File "c:\Users\mmai\.vscode\extensions\ms-python.python-2019.8.30787\pythonFiles\lib\python\ptvsd\__main__.py", line 432, in main
run()
File "c:\Users\mmai\.vscode\extensions\ms-python.python-2019.8.30787\pythonFiles\lib\python\ptvsd\__main__.py", line 316, in run_file
runpy.run_path(target, run_name='__main__')
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\runpy.py", line 263, in run_path
pkg_name=pkg_name, script_name=fname)
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\runpy.py", line 96, in _run_module_code
mod_name, mod_spec, pkg_name, script_name)
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\runpy.py", line 85, in _run_code
exec(code, run_globals)
File "c:\Users\mmai\Documents\Python\Mail.py", line 1043, in <module>
OEM()
File "c:\Users\mmai\Documents\Python\Mail.py", line 168, in __init__
self.mailMe()
File "c:\Users\mmai\Documents\Python\Mail.py", line 1035, in mailMe
s.send_message(msg)
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\smtplib.py", line 964, in send_message
g.flatten(msg_copy, linesep='\r\n')
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\email\generator.py", line 116, in flatten
self._write(msg)
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\email\generator.py", line 181, in _write
self._dispatch(msg)
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\email\generator.py", line 214, in _dispatch
meth(msg)
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\email\generator.py", line 427, in _handle_text
if _has_surrogates(msg._payload) and not self.policy.cte_type=='7bit':
File "C:\Users\mmai\AppData\Local\Programs\Python\Python37-32\lib\email\utils.py", line 57, in _has_surrogates
s.encode()
AttributeError: 'list' object has no attribute 'encode'
It seems there is a problem with s.send_message(msg) but i can't wrap my head around it. Sender and receiver are both a string and not a list.
Solved it by adding msg.add_attachment(htmlTable)
Upvotes: 0
Views: 9824
Reputation: 1
if receiver is a list, then use
for i in range(len(receiver)):
s.sendmail(message['From'], receiver[i], message.as_string())
Upvotes: 0