random
random

Reputation: 487

Byte array to float

I am trying to cast a float into a byte array of length 4, and then back again. But I it doesn's seems to work.

Here's what I've done:

byte[] b = BitConverter.GetBytes(90);
float fb = BitConverter.ToSingle(b, 0);

I expected fb = 90, but it's 1.26E-43.

I know that my converter is little endian, so I've also tried to reverse the array, like this:

byte[] b = BitConverter.GetBytes(90);
Array.Reverse(b);
float fb = BitConverter.ToSingle(b, 0);

Then I got the answer fb = 9.0E+15.

Any ideas? Thanks in advance!

Upvotes: 5

Views: 1368

Answers (3)

Jeroen van Langen
Jeroen van Langen

Reputation: 22083

You need to change the input on the GetBytes, it's an integer now.

It's now getting the bytes on how the integer is stored and interpretate as how a float would be stored in memory.

Change it to a float.

Try:

byte[] b = BitConverter.GetBytes(90f);  // <-- add an f for floats.
Array.Reverse(b);
float fb = BitConverter.ToSingle(b, 0);

Upvotes: 6

Ren&#233; Vogt
Ren&#233; Vogt

Reputation: 43936

90 is a literal that is interpreted by the compiler as Int32, not as Single. So you call the wrong overload of GetBytes().

Use: byte[] b = BitConverter.GetBytes(90f);

to tell the compiler you want to call GetBytes(float).

Upvotes: 6

D Stanley
D Stanley

Reputation: 152624

BitConverter.GetBytes(90); will give you the bytes for the integer value of 90. Since you want the bytes for the float value, you need to specify that:

BitConverter.GetBytes((float)90.0);

or

BitConverter.GetBytes(90.0f);

Upvotes: 8

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