CODEWITHSUNDEEP
sqloracle-databaselag
Sid
Sid

Reputation: 582

Update previous days count using LAG function in ORACLE

I have a table with columns as product, txn_date and no_of_txns. One more column prev_day_txn added recently to the column. Data is something like below:

Product   TXN_DATE  NO_OF_TXNS 

AA         1-JAN-19      100
AA         2-JAN-19      180
AA         3-JAN-19      290

With the new column added, data in the column should be populated with previous day's data. Output should be something like below:

Product       TXN_DATE     NO_OF_TXNS  PREV_DAY_TXN

    AA         1-JAN-19      100          0
    AA         2-JAN-19      180         100
    AA         3-JAN-19      290         180

I am trying to update the data using lag function, but getting error SQL Error: ORA-30483: window functions are not allowed hereSame query is working fine in select clause. This is what I tried:

update PRD_DTLS set PREV_DAY_TXN = LAG(NO_OF_TXNS, 1, 0) OVER (ORDER BY PRODUCT, TXN_DATE);

Can someone help me with the query. Thanks.

Upvotes: 1

Views: 626

Answers (2)

Popeye
Popeye

Reputation: 35920

You can use MERGE:

MERGE INTO PRD_DTLS A USING 
(
  SELECT
      PRODUCT,
      TXN_DATE,
      LAG(NO_OF_TXNS) OVER(
          PARTITION BY PRODUCT
          ORDER BY
              TXN_DATE
      ) AS PREV_TXN
  FROM
      PRD_DTLS 
)
B ON ( A.PRODUCT = B.PRODUCT
       AND A.TXN_DATE = B.TXN_DATE )
WHEN MATCHED THEN UPDATE SET A.PREV_DAY_TXN = CASE
    WHEN B.PREV_TXN IS NOT NULL THEN B.PREV_TXN
    ELSE 0
END;

Cheers!!

Upvotes: 2

Gordon Linoff
Gordon Linoff

Reputation: 1270573

One method uses a subquery:

UPDATE PRD_DTLS pd
    SET PREV_DAY_TXN = (SELECT COALESCE(MAX(NO_OF_TXNS) KEEP (DENSE_RANK FIRST ORDER BY TXN_DATE DESC), 0)
                        FROM PRD_DTLS pd2
                        WHERE pd2.PRODUCT = pd.PRODUCT AND
                              pd2.TXN_DATE < pd.TXN_DATE
                       );

Upvotes: 0

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