CODEWITHSUNDEEP
pythonpython-3.xweb-scraping
robots.txt
robots.txt

Reputation: 137

Can't parse a video link from a webpage using requests

I'm trying to get a youtube video link connected to a certain webpage. I've written a script to fetch that link but I've ended up getting an image link instead.

Webpage address

I've tried:

import requests
from bs4 import BeautifulSoup

url = 'find the link above'

def get_youtube_link(link):
    res = requests.get(link, headers={'User-Agent':'Mozilla/5.0'})
    soup = BeautifulSoup(res.text,'lxml' )
    youtube_link = soup.select_one("img[class='sleepy-load'][data-id^='video']")['data-original']
    print(youtube_link )

if __name__ == '__main__':
    get_youtube_link(url)

Output I'm getting:

//img.youtube.com/vi/tlgcDTLgNvg/default.jpg

As the link is not attached to that video so i could not show here how the link might look like.

This is how that video look like in that page: enter image description here

How can i scrape that video link from that page?

Upvotes: 0

Views: 72

Answers (1)

Mohit Solanki
Mohit Solanki

Reputation: 2130

If you are able to fetch //img.youtube.com/vi/tlgcDTLgNvg/default.jpg here the tlgcDTLgNvg is the youtube video id, the youtube link would be

video_id = "tlgcDTLgNvg"
youtube_link = https://youtu.be/{}.format(video_id)

Upvotes: 2

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