Reputation: 160
When my friend had his interview yesterday, he was asked a question: Implement a function that allocates memory space without using the *alloc or new operator, and the function should return a pointer to the address. Neither he nor I can find the answer.
Upvotes: 8
Views: 6922
Reputation: 2666
Depending on your platform you have a few options:
sbrk
is also an option, but its use is discouraged and it's no longer
part of POSIX.mmap
(or VirtualAlloc
or CreateFileMapping
on
Windows) as a source of memory, but if you want memory chunks smaller
than whole pages you'll still need to write some code to manage the
memory these functions return.Your allocator should ensure memory is properly aligned for your platform:
on some systems, unaligned memory access is an invalid operation and on
others there's a performance hit vs. aligned access. In real, production
code you'd also likely want to provide a free
operation to avoid taking
over all the system's memory and locking to make your heap thread-safe.
Upvotes: 3
Reputation: 5414
A super simple one that never frees.
class allocator{
static char mem_pool[1048576];
char* place;
public:
allocator(){
place = mem_pool;
}
allocator(const allocator& a){
place = a.place;
}
char* alloc(size_t size){
char* ret = place;
place += size;
return ret;
}
}
Upvotes: 1
Reputation: 96939
I think the question is more of a puzzle than a question that shows experience with programming. My solution would be allocating a global byte-array, that would be used instead of the heap:
char heap[MAX_ALLOWED_MEM];
/*
The following function uses 'heap' as raw memory!
void* like_malloc(size_t bytes);
...
*/
Upvotes: 16
Reputation:
You can do it via a system call such as sbrk(), rather than using a C library function or a C++ language feature. There is absolutely no reason to do this, however, so this is a very crappy question.
Upvotes: 2