CODEWITHSUNDEEP
graphql
ttmt
ttmt

Reputation: 4984

graphQl - return all in db

I'm really new to graphQL

I have a simple graphQL schema here

const graphql = require('graphql');
const _ = require('lodash');

const {
  GraphQLObjectType,
  GraphQLString,
  GraphQLSchema,
  GraphQLID
} = graphql

const books = [
  { name: "book 1", genre: "book-1", id: "1" },
  { name: "book 2", genre: "book-2", id: "2" },
  { name: "book 3", genre: "book-3", id: "3" }
]

const BookType = new GraphQLObjectType({
  name: 'Book',
  fields: () => ({
    id: { type: GraphQLID },
    name: { type: GraphQLString },
    genre: { type: GraphQLString }
  })
})

const RootQuery = new GraphQLObjectType({
  name: 'RootQueryType',
  fields: {
    book: {
      type: BookType,
      args: { id: { type: GraphQLID } },
      resolve(parent, args) {
        return _.find(books, { id: args.id })
      }
    }
  }
})

module.exports = new GraphQLSchema({
  query: RootQuery
})

I can return one book using the id

const RootQuery = new GraphQLObjectType({
  name: 'RootQueryType',
  fields: {
    book: {
      type: BookType,
      args: { id: { type: GraphQLID } },
      resolve(parent, args) {
        return _.find(books, { id: args.id })
      }
    }
  }
})

How would I return all the books, I was thinking something like:

const RootQuery = new GraphQLObjectType({
  name: 'RootQueryType',
  fields: {
    book: {
      type: BookType,
      args: {},
      resolve(parent, args) {
        return _.find(books, {})
      }
    }
  }
})

Upvotes: 1

Views: 85

Answers (1)

ttmt
ttmt

Reputation: 4984

const RootQuery = new GraphQLObjectType({
  name: 'RootQueryType',
  fields: {
    book: {
      type: BookType,
      args: { displayall: { type: GraphQLID } },
      resolve(parent, args) {
        return _.find(books, { displayall: args.displayall })
      }
    }
    books:{
        type: new GraphQLList(BookType),
          resolve(parent, args) {
            return books
          }
        }
  }
})

Upvotes: 1

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