CODEWITHSUNDEEP
bashshellaix
user3559721
user3559721

Reputation: 134

How to find passing argument value of a running script?

I have an AIX production server, there is a script A.sh running on it. i have no root access for this server. i want to find out argument passing value of this A.sh script. How can i get this value?

Is there any provision inside /proc/processID?

The following is not working. I tried by generating a script:

echo "Hello $1 $2 $3"

while [ 1 ]
do
   sleep 2
   echo $$
done

Then I run this script by 

test.sh 1  2 3

Output:

$ cat /proc/3107/cmdline
-bash$

As per suggestion by @Cyrus suggestion I expect

1 2 3

which are the arguments I passed in, but it is not working like that.

Upvotes: 1

Views: 200

Answers (2)

1218985
1218985

Reputation: 8032

This should work:

cat /proc/3107/cmdline | tr '\0' ' ';

Alternatively you can use:

ps -ef | grep script.sh | grep -v grep

where script.sh is the name of your script which is running now.

Steps for verifying this:

  1. Create a script named script.sh and paste the below code in it:

    #!/bin/bash
while :
do
  echo "Press [CTRL+C] to stop.."
  sleep 1
done

  2. Save the file (:wq! from vi editor ).

  3. Make it executable by 

    chmod a+x script.sh

  4. Run the script by issuing command-line options like this:

    ./script.sh var1 val1 var2 val2 var2 val4

  5. Open another terminal (duplicate session) and issue:

    ps -ef | grep script.sh | grep -v grep

You should be able to see something like this:

username 12227  2268  0 07:48 pts/98   00:00:00 /bin/bash ./script.sh var1 val1 var2 val2 var2 val4 var4

Upvotes: 1

UtLox
UtLox

Reputation: 4164

you can try:

cat /proc/PROCESSID/cmdline

Upvotes: 2

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