CODEWITHSUNDEEP
pythonpython-3.xdictionary
code_explorer
code_explorer

Reputation: 480

Sort based Dictionary of Dictionary of Dictionary Values?

I have a dictionary like this 

d = {
    'Benefits': {
        1: {
            'BEN1': {
                'D': [{'description': 'D1'}],
                'C': [{'description': 'C1'}]
            }
        },
        2: {
            'BEN2': {
                'D': [{'description': 'D2'}],
                'C': [{'description': 'C2'}]
            }
        }
    }
}

I am trying to sort dictionary based on KEY OF LAST VALUES(LIST).

FOR EXAMPLE

I am looking for get dictionary value like 'C' IN first and 'D' in second

I'm trying to get correct order. Here is code:

d1 = collections.OrderedDict(sorted(d.items()))

Unfortunately didn't get correct result

This is my expected output

{'Benefits':
 {1:
  {'BEN1':
   {'C':[{'description': 'C1'}], 'D': [{'description': 'D1'}]
   }
  },
 2:
  {'BEN2':
   {'C': [{'description': 'C2'}], 'D': [{'description': 'D2'}]
   }
  }
 }
}

I am using python 3.5 . I am trying to get order like this

{'C':[{'description': 'C1'}], 'D': [{'description': 'D1'}]}

Upvotes: 0

Views: 78

Answers (2)

Booboo
Booboo

Reputation: 44043

The following code will sort any dictionary by its key and recursively sort any dictionary value that is also a dictionary by its key and makes no assumption as to the content of the dictionary being sorted. It uses an OrderedDict but if you can be sure it will always run on Python 3.6 or greater, a simple change can be made to use a dict.

from collections import OrderedDict

d = {
    'Benefits': {
        1: {
            'BEN1': {
                'D': [{'description': 'D1'}],
                'C': [{'description': 'C1'}]
            }
        },
        2: {
            'BEN2': {
                'D': [{'description': 'D2'}],
                'C': [{'description': 'C2'}]
            }
        }
    }
}

def sort_dict(d):
    items = [[k, v] for k, v in sorted(d.items(), key=lambda x: x[0])]
    for item in items:
        if isinstance(item[1], dict):
            item[1] = sort_dict(item[1])
    return OrderedDict(items)
    #return dict(items)

print(sort_dict(d))

See demo

Upvotes: 2

pnv
pnv

Reputation: 3135

d1 = collections.OrderedDict(sorted(d.items()))

This is not working because it is sorting only on the Benefits item. Here you want to sort inner items, so we have to reach the inner items and sort them.

d1 = {'Benefits': {}}
for a_benefit in d['Benefits']:
    d1['Benefits'][a_benefit] = {}
    for a_ben in d['Benefits'][a_benefit]:
        d1['Benefits'][a_benefit][a_ben] = dict(collections.OrderedDict(sorted(d['Benefits'][a_benefit][a_ben].items())))

Upvotes: 0

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