a_random_programmer
a_random_programmer

Reputation: 148

Is it possible to validate when an entered password is wrong?

When writing an auto-it for safari with selenium, is it possible to know if a password inserted into a website login is wrong?

I've tried using try: and except:, but selenium doesn't raise an error when the password is wrong.

an example would be:

from selenium import webdriver
from selenium.webdriver.common.keys import Keys

driver=webdriver.Safari()
driver.get(r'website')
usr=driver.find_element_by_name(r'username')
usr.clear()
usr.send_keys(r'username')
pas=driver.find_element_by_name(r'password')
pas.clear()
pas.send_keys(r'password')
pas.send_keys(Keys.RETURN)

Upvotes: 0

Views: 1147

Answers (2)

undetected Selenium
undetected Selenium

Reputation: 193208

To validate if a username/password inserted into a website login is wrong you can use a try/catch{} block and you can use the following Locator Strategies:

  • Code Block:

    from selenium import webdriver
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support.ui import WebDriverWait
    from selenium.webdriver.support import expected_conditions as EC
    from selenium.common.exceptions import TimeoutException
    
    chrome_options = webdriver.ChromeOptions()
    chrome_options.add_argument("start-maximized")
    driver = webdriver.Chrome(options=chrome_options, executable_path=r'C:\Utility\BrowserDrivers\chromedriver.exe')
    driver.get("https://auth.florimont.ch/cas/login?service=https%3A%2F%2Fflore.florimont.ch%2Fhome")
    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input#username"))).send_keys("a_random_programmer")
    driver.find_element_by_css_selector("input#password").send_keys("a_random_programmer")
    driver.find_element_by_css_selector("input.btn-submit").click()
    try:
        WebDriverWait(driver, 20).until(EC.text_to_be_present_in_element((By.XPATH, "//h2[text()='Enter your Username and Password']//preceding::div[1]"), "Invalid credentials."))
        print("Invalid Login")
    except TimeoutException as e:
        print("Valid Login")
    driver.quit()
    
  • Console Output:

    Invalid Login
    

Upvotes: 0

KunduK
KunduK

Reputation: 33384

Use WebDriverWait and element_to_be_clickable and following css selector.

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver=webdriver.Chrome()
driver.get(r'https://auth.florimont.ch/cas/login;jsessionid=8B5A3B65779756F3CF71ACB41E578AC3?service=https%3A%2F%2Fflore.florimont.ch%2Fhome')
usr=driver.find_element_by_name(r'username')
usr.clear()
usr.send_keys(r'username')
pas=driver.find_element_by_name(r'password')
pas.clear()
pas.send_keys(r'password')
pas.send_keys(Keys.RETURN)
print(WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"#fm1 #msg"))).text)

Print on console:

Invalid credentials.

Browser snapshot:

enter image description here

Upvotes: 2

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