CODEWITHSUNDEEP
bashshellgetopts
Developer
Developer

Reputation: 6350

How to take 2 argument from getopts

I am creating a bash script that will two argument from the user from command line . But i am not sure how I can take 2 argument from the user and both arguments are required if not passed will show error and return from the script . Below is the code i am using to take argument from the user , but currently my getopts is taking only one argument. 

optspec="h-:"
while getopts "$optspec" optchar; do
  case "${optchar}" in
    -)
      case "$OPTARG" in
        file)
          display_usage ;;
        file=*)
          INPUTFILE=${OPTARG#*=};;
      esac;;
    h|*) display_usage;;
  esac
done

How could i add an an option to take one more args from command line. Like below

script.sh --file="abc" --date="dd/mm/yyyy"

Upvotes: 1

Views: 774

Answers (1)

KamilCuk
KamilCuk

Reputation: 141020

getopts does not support long arguments. It only supports single letter arguments.

You can use getopt. It is not as widely available as getopts, which is from posix and available everywhere. getopt will be for sure available on any linux and not only. On linux it's part of linux-utils, a group of most basic utilities like mount or swapon.

Typical getopt usage looks like:

if ! args=$(getopt -n "your_script_name" -oh -l file:,date: -- "$@"); then
    echo "Error parsing arguments" >&2
    exit 1
fi
# getopt parses `"$@"` arguments and generates a nice looking string
# getopt .... -- arg1 --file=file arg2 --date=date arg3
# would output:
# --file file --date date -- arg1 arg2 arg3
# the idea is to re-read bash arguments using `eval set`
eval set -- "$args"
while (($#)); do
   case "$1" in
   -h) echo "help"; exit; ;;
   --file) file="$2"; shift; ;;
   --date) date="$2"; shift; ;;
   --) shift; break; ;;
   *) echo "Internal error - programmer made an error with this while or case" >&2; exit 1; ;;
   esac
   shift
done

echo file="$file" date="$date"
echo Rest of arguments: "$@"

Upvotes: 3

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