CODEWITHSUNDEEP
.netinteger-overflow
Andy Rose
Andy Rose

Reputation: 16974

Why does this integer overflow occur?

I've wrapped a dll method that has an integer as an out parameter in a web service. In testing I was finding that when I was expecting -1 I was getting 65,535 instead. I realised that the dll was using 16 bit integers and I was specifying the standard .NET 32bit integer when referencing the external dll in my code. this was quickly fixed by specifying a 16 bit integer and all is well.

My question is why did this happen? I could understand an overflow occuring if I was trying to fit a 32 bit integer in a 16 bit integer but I am not so sure why this happens the other way round. Clearly my understanding of this type of casting between types is a little lacking so any guidance will be greatly appreciated.

Upvotes: 3

Views: 507

Answers (2)

Jason Cohen
Jason Cohen

Reputation: 83011

This happened because of the type-casting.

You don't actually send 16-bit integers on the call stack -- they're still 32-bit. So what the DLL returned exactly was:

0x0000ffff

If you cast this to e.g. sint16, this is -1, but if this is 32-bits, this is 65535.

Upvotes: 2

Paul Tomblin
Paul Tomblin

Reputation: 182772

A 16 bit integer "-1" has all 16 bits set. If you set the bottom 16 bits of a 32 bit integer, the value is 65,535. For an explanation of the internal representation of negative ints, have a look at this article.

Upvotes: 6

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