CODEWITHSUNDEEP
javaregex
Dan
Dan

Reputation: 1110

Regex causing Pattern Syntax Exception

I am trying to create a #replaceAll regex to file out certain characters.

I tried the following

msg.replaceAll("[^\\w~!@#$%^&*()-=_+`[]{}\\|:;'\"<>,./\\]", "");

but it gave me this error

INFO Caused by: java.util.regex.PatternSyntaxException: Unclosed character class near index 36
07.09 00:07:24 [Server] INFO [^\w~!@#$%^&*()-=_+`[]{}\|:;'"<>,./\]
07.09 00:07:24 [Server] INFO ^

I've tried searching online but don't know exactly what I'm doing wrong.

Upvotes: 0

Views: 83

Answers (2)

Emma
Emma

Reputation: 27723

My guess is that maybe this expression might be desired or close to one:

import java.util.regex.Matcher;
import java.util.regex.Pattern;


public class re{

    public static void main(String[] args){


        final String regex = "[^\\w~!@#$%^&*()=_+`\\[\\]{}|:;'\"<>,.\\\/-]";
        final String string = "ábécédééefg";
        final String subst = "";

        final Pattern pattern = Pattern.compile(regex);
        final Matcher matcher = pattern.matcher(string);

        final String result = matcher.replaceAll(subst);

        System.out.println(result);

    }
}

Output

bcdefg

If you wish to explore/simplify/modify the expression, it's been explained on the top right panel of regex101.com. If you'd like, you can also watch in this link, how it would match against some sample inputs.

Upvotes: 1

flyingfox
flyingfox

Reputation: 13506

For your regex expression,you have add \\ before the last ] and do not escape for the first [,and also you need to escape -,after changing it to 

[^\w~!@#$%^&*()\-=_+`\[\]{}\|:;'\"<>,./]

it works fine in my side

msg = msg.replaceAll("[^\\w~!@#$%^&*()\\-=_+`\\[\\]{}\\|:;'\\\"<>,./]", "");

Upvotes: 1

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