CODEWITHSUNDEEP
c#winapimodal-dialogoutlook-2007inspector
CodeMinion
CodeMinion

Reputation: 653

How to : Given HWND, discover if window is Modal or not

For any given window I handle, I need a way to find out whether or not the given window is Modal.

Far as I can tell, there are no methods that do exactly that, which is why I need some clever workaround to work this out!

Help is appreciated!

EDIT : Why is my GetWindow(,GW_OWNER) failing? :(

    [DllImport("user32.dll", SetLastError = true, CharSet = CharSet.Auto)]
    internal static extern IntPtr FindWindow(string lpClassName, string lpWindowName);
    [DllImport("user32.dll", SetLastError = true)]
    internal static extern IntPtr GetWindow(IntPtr hWnd, GetWindow_Cmd uCmd);
    [DllImport("user32.dll", ExactSpelling = true)]
    internal static extern IntPtr GetAncestor(IntPtr hwnd, GetAncestor_Flags gaFlags);
    [DllImport("user32.dll", SetLastError = false)]
    internal static extern IntPtr GetDesktopWindow();
    [DllImport("user32.dll", SetLastError = true)]
    internal static extern int GetWindowLong(IntPtr hWnd, int nIndex);

    const UInt32 WS_DISABLED = 0x8000000;


    internal enum GetAncestor_Flags
    {
        GetParent = 1,
        GetRoot = 2,
        GetRootOwner = 3
    }

    internal enum GetWindow_Cmd : uint
    {
        GW_HWNDFIRST = 0,
        GW_HWNDLAST = 1,
        GW_HWNDNEXT = 2,
        GW_HWNDPREV = 3,
        GW_OWNER = 4,
        GW_CHILD = 5,
        GW_ENABLEDPOPUP = 6
    }



IntPtr _inspHwnd = FindWindow("rctrl_renwnd32", inspector.Caption); // searching for a window with this name
        if (_inspHwnd.ToInt32() != 0) // found window with this name
        {
            IntPtr _ownerHwnd = GetWindow(_inspHwnd, GetWindow_Cmd.GW_OWNER);
            if (_ownerHwnd.ToInt32() != 0)
            {
                IntPtr _ancestorHwnd = GetAncestor(_ownerHwnd, GetAncestor_Flags.GetParent);
                if (_ancestorHwnd == GetDesktopWindow())
                {
                    if (GetWindowLong(_ancestorHwnd, -16) == WS_DISABLED) 
                    { 
                        // inspector is probably modal if you got all the way here
                        MessageBox.Show("modal flag tripped");
                    }
                }
            }
        }

Upvotes: 12

Views: 6890

Answers (3)

BrendanMcK
BrendanMcK

Reputation: 14488

Modal windows usually work by disabling their owner, where the owner is a top-level window. So if you test for this situation, you should catch whether a dialog is modal or not.

  • Check that the HWND is actually a top-level dialog, and not a child window
  • Get the owner (GetWindow(GW_OWNER))
  • Check that the owner is itself a top-level window (eg. GetAncestor(GA_PARENT)==GetDesktopWindow())
  • Check that the owner is disabled (GetWindowLong(GWL_STYLE) & WS_DISABLED)

That should catch all standard Win32-style modal dialogs.

Note that parent and owner are subtly different concepts; it's the owner you want to check here. This can get confusing, because GetParent can return the owner... - more details from Raymond Chen here.

Upvotes: 10

eugen_nw
eugen_nw

Reputation: 159

I'm not certain that BrendanMck's solution will always be correct. Let's say that window W displays first a modeless dialog A and then a modal dialog B. Both A and B have W as their parent window. At the time B was displayed, W became disabled and as such applying the algorithm to both A and B will report both of them as being modal dialogs.

Upvotes: 3

Albert EInstein
Albert EInstein

Reputation: 1

I just wrote GetWindowLong(GetWindow(Hwnd, GW_OWNER), GWL_STYLE) & WS_DISABLED & WS_POPUP in my code.

Upvotes: -2

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