CODEWITHSUNDEEP
c++eigen
EigenGrau
EigenGrau

Reputation: 57

Map from std::vector<unsigned> to Eigen::VectorXi

Is there a way to directly map a std::vector<unsigned> to an Eigen::VectorXi in the following fashion?

    std::vector<unsigned> a = {1,2,3,4,5};
    Eigen::VectorXi c = Eigen::VectorXi::Map(a.data(), a.size());

I'd like to skip the following step in between:

    std::vector<int> b(a.begin(),a.end());

Upvotes: 0

Views: 908

Answers (1)

Avi Ginsburg
Avi Ginsburg

Reputation: 10596

Your line

Eigen::VectorXi c = Eigen::VectorXi::Map(a.data(), a.size());

doesn't "directly map a std::vector<unsigned> to an Eigen::VectorXi," rather, it copies the data to a new Eigen::VectorXi. If you want to wrap the existing data array with Eigen functionality, you should use something like:

Eigen::Map<Eigen::VectorXi> wrappedData(a.data(), a.size());

You can then use use wrappedData as you would any other VectorXi with the exception of resizing the underlying data (that's still owned by the std::vector). See the documentation for more details.

If you're trying to avoid copying the data to a std::vector<int> then you can use a "custom" matrix type, i.e.

typedef Eigen::Matrix<unsigned int, Eigen::Dynamic, 1> VectorXui;
Eigen::Map<VectorXui> wrappedData(a.data(), a.size());

Upvotes: 4

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