Reputation: 21
OLD MACDONALD: Write a function that capitalizes the first and fourth letters of a name
I'm trying to write this in different ways and I also feel like there's an easier way to do this. Cant, you directly apply it without getting all the other words of a string? Or a split or something?
Here is one of my attempts at trying it another way. I'm trying to do it with a for
AND an if
statement too. Any help is appreciated.
def old_macdonald(words):
wordletter = words[0]
fourthletter = words[3]
newword = []
for i,l in enumerate(words):
if i[0]:
newword = l.capatalize
return newword
if i[3]:
newword = l.capatalize
return newword
Upvotes: 2
Views: 16458
Reputation: 97
This one worked
def old_macdonald(name):
word = ''
for index,letter in enumerate(name):
if index == 0 or index == 3:
letter = name[index].capitalize()
word += letter
else:
word += letter
return word
Upvotes: 1
Reputation: 41
def cap(name):
first = name[0]
mid = name[1:3]
second = name[3]
rest = name[4:]
return first.upper() + mid + second.upper() + rest
cap('kahasdfn')
Upvotes: 1
Reputation: 51
This is the most legible way IMO
def old_macdonald(name):
mylist = list(name)
mylist[0] = mylist[0].upper()
mylist[3] = mylist[3].upper()
return ''.join(mylist)
Upvotes: 5
Reputation: 37512
def old_macdonald(s):
return s[0:3].capitalize() + s[3:].capitalize()
Upvotes: 0
Reputation: 63
def old_macdonald(name):
letters = list(name)
for index in range(len(name)):
if index == 0:
letters[index] = letters[index].upper()
elif index == 3:
letters[index] = letters[index].upper()
return "".join(letters)
This one worked for me
Upvotes: 1
Reputation: 1
def old_macdonald(s):
w=""
for i in s:
t=s.index(i)
if t==0:
w=w+i.upper()
elif(t==3):
w=w+i.upper()
else:
w=w+i
print(w)
old_macdonald("aman")
Upvotes: 0
Reputation: 331
I like writing it this way:
def old_macdonald(word):
indices = (0, 4)
return ''.join(c.capitalize() if index in indices else c for index, c in enumerate(word))
Although it's a little long, so you might prefer writing it more clearly as:
def old_macdonald(word):
indices = (0, 4)
new_string = []
for index, c in enumerate(word):
new_string.append(c.capitalize() if index in indices else c)
return ''.join(new_string)
Upvotes: 0
Reputation: 17156
def old_macdonald(s):
return ''.join([s[:1].upper(), s[1:3], s[3:4].upper(), s[4:]])
# s[:1] - letter index 0 (first)
# s[1:3] - letters index 1-2
# s[3:4] - letter index 3 (fourth)
# s[4:] - letters index 4 onward
test_string = "abcdefghijklmnopqr"
print(old_macdonald(test_string )) # AbcDefghijklmnopqr
Upvotes: 0
Reputation: 2665
A pretty simple and modifiable example.
def old_mcdonald(word):
indexes = (0,3) #letters i want to cap
new_word = "".join([v.capitalize() if i in indexes else v for i,v in enumerate(word)])
return new_word
Upvotes: 0
Reputation: 1112
Here's one way. You do need to split the string into a list of characters to change individual characters, because strings are immutable, and then use join afterward to convert them back into a string.
def old_macdonald(name):
letters = list(name)
for letter_to_capitalize in [1, 4]:
if len(letters) >= letter_to_capitalize:
letters[letter_to_capitalize - 1] = letters[letter_to_capitalize - 1].upper()
return "".join(letters)
Upvotes: 0