CODEWITHSUNDEEP
batch-file
user12044181
user12044181

Reputation:

How do I perform a string replace in batch on %* arguments?

I would like to perform a string replace on the arguments given to my batch file. For example, replacing the %~dp0 argument from back slashes to forward slashes.

I have tried: %~dp0:\=/ and %~dp0:\=/%, both do not replace the slashes. The only possible solution I can do is messy:

set dir=%~dp0
set dir=%dir:\=/%

Is there a better way to do it without setting a separate variable and hopefully in a single line?

Upvotes: 0

Views: 627

Answers (1)

BDM
BDM

Reputation: 3900

Short answer - No.

String manipulations do not work for parsed arguments (%1) or for loop tokens (%%i). It is generally considered bad practice to not save your parsed arguments into named variables for two reasons:

Readability - transferring your arguments into named variables will increase your ability to debug and understand your code after you have written it.

Overwriting - any call:function param1 param2 occurrences in your scripts will overwrite the argument values within that scope.

Upvotes: 2

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