Reputation: 33
I am still not able to use regular expressions by heart, thus could not find a final solution to strip out background color,font-family and color property from table with RegEx, but leave all styles
I have tried regular expression to remove all styles except color and background property. But actually I want to remove background color,font-family and color property but leave all styles
if(isset($_REQUEST["Save"])) {
$VariantName = $_REQUEST["name"];
$desc = preg_replace('/(<[^>]+\s+)(?:style\s*=\s*"(?!(?:|[^"]*[;\s])color\s*:[^";]*)(?!(?:|[^"]*[;\s])background-color\s*:[^";]*)[^"]*"|(style\s*=\s*")(?=(?:|[^"]*[;\s])(color\s*:[^";]*))?(?=(?:|[^"]*)(;))?(?=(?:|[^"]*[;\s])(background-color\s*:[^";]*))?[^"]*("))/i', '', $VariantName);
echo $desc;
}
This
<p style="font-family:Garamond;font-size:8px;line-height:14px;color:#FF0000;background-color:red;">example</p>
should become:
<p style="font-size:8px;line-height:14px;">example</p>
Upvotes: 3
Views: 1169
Reputation: 3721
I don't recommend this but you can use this regular expression to remove the CSS
props you want:
/(background-color|color|font-family)\:\#?\w+\;/i
Example:
<?php
//Enter your code here, enjoy!
$string = '<p style="font-family:Garamond;font-size:8px;line-height:14px;color:#FF0000;background-color:red;">example</p>';
$pattern = '/(background-color|color|font-family)\:\#?\w+\;/i';
$replacement = '';
echo preg_replace($pattern, $replacement, $string);
Upvotes: 1