CODEWITHSUNDEEP
carrayspointersdynamicmalloc
Manav Kapil
Manav Kapil

Reputation: 11

Unable to allocate dynamic memory segmentation error

I'm trying to allocate memory to an array using a function. I have passed pointer by reference(using double pointer). The code compiles but segmentation error is thrown during run time. 

#include<stdio.h>
#include<stdlib.h>
//funct to read array 

int read(int **v){
    int n,ele;
    printf("enter number of elements \n");
    scanf("%d",&n);
    //p=(int*)malloc(n*(sizeof(int));
        *v= (int*)malloc(n * sizeof(int)); 
    for(int i=0;i<n;i++)
    {
        //printf("enter %d th element \n",i);
        scanf("%d",&ele);
        *v[i]=ele;
    }
    return n;
}


void main()
{
    int *p=NULL;
    int sz=read(&p);
    for(int i =0;i<5;i++)
    {
        printf("%d",p[i]);
    }
}

Upvotes: 0

Views: 98

Answers (1)

fas
fas

Reputation: 1413

Here is the error: *v[i]=ele;. In this case, you've first subscripted array and then have dereferenced it. https://en.cppreference.com/w/c/language/operator_precedence. Change it to (*v)[i]=ele; and it will work.

UPD. Don't forget to free(p) to avoid memory leaks.

Upvotes: 3

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