CODEWITHSUNDEEP
python
Diwakar SHARMA
Diwakar SHARMA

Reputation: 581

Need to Find dynamically changing integer from string based text file

I need to convert or fetch values of integers at the end of the string from following 4 string from a text file .

Integer values at the last of each string constantly change, which is a problem here. How can i implement it through regex?

string1 = ('Port A Rx frames:\t', '1003')

string2 = ('Port B Rx frames:\t', '1000')

string3 = ('Tx FrameCount :', 'Port A', '1001')

string4 = ('Tx FrameCount :', 'Port B', '1001')

I tried regular expression but it is not working:

import os
import re

f1 = open("C:/path/Desktop/set_initial.txt")

s1 = "('Port A Rx frames:\t', '1003')"
s2 = "('Port B Rx frames:\t', '1000')"
s3 = "('Tx FrameCount A :', 'txstreamresults', '1001')"
s4 = "('Tx FrameCount B :', 'txstreamresults', '1001')"

for line in f1:

    a = int(re.search(r'\d+', s1).group())
    b = int(re.search(r'\d+', s2).group())
    c = int(re.search(r'\d+', s3).group())
    d = int(re.search(r'\d+', s4).group())

print(a)
print(b)
print(c)
print(d)

expected output : 

1003
1000
1001 
1001

observed output but i have kept above 4 strings as static however integer values at last of each string will dynamically change: 

1003 
1000 
1001 
1001

Upvotes: 0

Views: 272

Answers (4)

CypherX
CypherX

Reputation: 7353

You could use re.findall('\d{4}', s) to get a list of 4-digit strings in s. The list could then be just joined or use index to get the first (and assuming the only result) since there is only one 4-digit number in each string.

Example

Option-1

import re

s1 = "('Port A Rx frames:\t', '1003')"
s2 = "('Port B Rx frames:\t', '1000')"
s3 = "('Tx FrameCount A :', 'txstreamresults', '1001')"
s4 = "('Tx FrameCount B :', 'txstreamresults', '1001')"

ss = [s1, s2, s3, s4]

[''.join(re.findall('\d{4}', s)) for s in ss]

Output

['1003', '1000', '1001', '1001']

Option-2

You join all strings together (assuming you could read the entire file as a single string)

re.findall('\d{4}', '\n'.join(ss))

Output

['1003', '1000', '1001', '1001']

Upvotes: 1

a_r
a_r

Reputation: 518

Taking that your variables like s1, s2 etc are taken directly from a text file, and it appears exactly as you have presented these variable's values in your code, eg:

s2 = "('Port B Rx frames:\t', '1000')"
s3 = "('Tx FrameCount A :', 'txstreamresults', '1001')"
s4 = "('Tx FrameCount B :', 'txstreamresults', '1001')"

You can use the following to get the 4 digit integer:

all_numbers = []
with open('number.txt', 'r') as opened_file:
    for line in opened_file:
        number = ''
        for e in line.split(',')[-1]:
            if e.isdigit():
                number = number+e
        value = int(number)
        all_numbers.append(value)
all_numbers

The variable value has the integer digit like 1001, 1000 etc. If you want to get the string form, ignore the conversion at value = int(number).

Upvotes: 1

Lê Tư Thành
Lê Tư Thành

Reputation: 1083

I hope you catch my idea about your issue.

import re
fname = "/path/to/set_initial.txt"
check_update = True
while check_update:
    readfile = open(fname, 'r').read()  # " a, 123 \n b, 234 \n c, 345"
    list_of_numbers = re.findall(r'\d+', readfile)  # ['123', '234', '345']
    if updating_file:   # traffic generator script run  <== MOST IMPORTANT
        check_update = True
    else:
        check_update = False

Upvotes: 1

Rakesh
Rakesh

Reputation: 82765

Looks like you just need.

import re
with open("C:/path/Desktop/set_initial.txt") as infile:
    for line in infile:
        if line.strip():
            a = re.search(r'(\d+)', line)
            if a:
                print(int(a.group(1)))

Upvotes: 1

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