CODEWITHSUNDEEP
python-3.x
yolon bsn
yolon bsn

Reputation: 89

printing all the binary posible with 3 length

while running this code its showing

digit(digit - 1, pref + str(0)) TypeError: unsupported operand type(s) for -: 'function' and 'int

def digit(n, pref):
    if digit == 0:
        print(pref)
    else:
        digit(digit - 1, pref + str(0))

        digit(digit - 1, pref + str(1))


print(digit(3, ''))

Upvotes: 0

Views: 22

Answers (2)

hiro protagonist
hiro protagonist

Reputation: 46921

this would be a simpler way:

def digit(n):
    for i in range(1<<n):
        print(f'{i:0{n}b}')

digit(3)

1<<n is just 2 to the power of n and then i print the number in binary with n binary places (filled by zero if necessary).

this could be shortened to 

n=3
print('\n'.join(f'{i:0{n}b}' for i in range(1<<n)))

which would then generate your output.

Upvotes: 0

Djaouad
Djaouad

Reputation: 22794

You're treating digit as if it was n in some places in your code, replace it with n and it'll work:

def digit(n, pref):
    if n == 0:
        print(pref)
    else:
        digit(n - 1, pref + '0') # just use '0', '1' instead of str(...)
        digit(n - 1, pref + '1')


digit(3, '')

Output:

000
001
010
011
100
101
110
111

Note that use can also use itertools.product for this task:

from itertools import product
print([''.join(p) for p in product('01', repeat=3)])

Output:

['000', '001', '010', '011', '100', '101', '110', '111']

Upvotes: 1

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