CODEWITHSUNDEEP
python
Brian Hartling
Brian Hartling

Reputation: 89

Logic using the difference between two integer variables

I have a game that goes through rounds, which have the variables, count1 and count2 as score. I am trying to create some logic that plays the while loop till someone reaches 9, but also has to be 2 points ahead.

I feel like I'm getting close. I'm pretty sure the first portion's right. I keep trying to change the Boolean and format to see if I can get it to work. 

while (count1 <= 9 and count2 <= 9) and ((count1 - count2 > 2) or (count2 - count1 > 2)):

Happy Path: The while loop loops through till someone gets to 9 and has a 2 point lead.

As far as errors go, it keeps going to end game since that is the else statement, which tells me that my logic is still a bit off.

Upvotes: 1

Views: 63

Answers (2)

Adrian Shum
Adrian Shum

Reputation: 40036

Let's deal with it bit-by-bit:

You want the loop keep running. When someone hit 9 points or more, and score difference is 2 or more, stop the loop.

Easiest translation will be:

# s1 and s2 representing score 1 and 2
while True:
    if (s1 >= 9 or s2 >= 9) and abs(s1 - s2) >= 2:
        break
    # do something

Which also implies, when the condition is NOT met, we keep going:

# s1 and s2 representing score 1 and 2
while not ((s1 >= 9 or s2 >= 9) and abs(s1 - s2) >= 2):
    # do something

Some basic boolean arithmetic simplify the condition:

# s1 and s2 representing score 1 and 2
while (s1 < 9 and s2 < 9) or abs(s1 - s2) < 2:
    # do something

For which the condition also reads correct: we keep looping while both scores are under 9, or (at least one reaches 9 and) score difference is less than 2.

Upvotes: 1

Selcuk
Selcuk

Reputation: 59228

You are keeping the loop running if one is ahead by 2 points while I believe you want the opposite:

while (count1 <= 9 and count2 <= 9) and ((count1 - count2 > 2) or (count2 - count1 > 2)):

I haven't seen the rest of your code, but this should probably work:

while (count1 < 9 and count2 < 9) or abs(count1 - count2) < 2:

Upvotes: 3

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