how to check if a particular directory exists in S3 bucket using python and boto3

Question

How to check if a particular file is present inside a particular directory in my S3? I use Boto3 and tried this code (which doesn't work):

import boto3

s3 = boto3.resource('s3')
bucket = s3.Bucket('my-bucket')
key = 'dootdoot.jpg'
objs = list(bucket.objects.filter(Prefix=key))
if len(objs) > 0 and objs[0].key == key:
    print("Exists!")
else:
    print("Doesn't exist")

Answer 1

Check this for checking folder is existed and not empty:

def folder_exists_and_not_empty(bucket_name: str, object_key: str) -> bool:
    '''
    Folder should exists. 
    Folder should not be empty.
    '''

    if not object_key.endswith('/'):
        object_key = object_key+'/' 
    
    s3 = boto3.resource("s3")
    bucket = s3.Bucket(bucket_name)
    current_object = [file.key for file in bucket.objects.filter(Prefix=object_key) if (file.key == object_key and (str(file.get()['ContentType']).startswith('application/x-directory')))]
    list_files = [file.key for file in bucket.objects.filter(Prefix=object_key) if (file.key != object_key)]

    return len(current_object) == 1 and len(list_files) > 0

Answer 2

import boto3
import botocore

client = boto3.client('s3')

result= client.list_objects_v2(Bucket='athenards', Prefix = 'cxdata')


for obj in result['Contents']:
    if obj['Key'] == 'cxdata/':
        print("true")

Answer 3

While checking for S3 folder, there are two scenarios:

Scenario 1

import boto3

def folder_exists_and_not_empty(bucket:str, path:str) -> bool:
    '''
    Folder should exists. 
    Folder should not be empty.
    '''
    s3 = boto3.client('s3')
    if not path.endswith('/'):
        path = path+'/' 
    resp = s3.list_objects(Bucket=bucket, Prefix=path, Delimiter='/',MaxKeys=1)
    return 'Contents' in resp

• The above code uses MaxKeys=1. This it more efficient. Even if the folder contains lot of files, it quickly responds back with just one of the contents.
• Observe it checks Contents in response

Scenario 2

import boto3

def folder_exists(bucket:str, path:str) -> bool:
    '''
    Folder should exists. 
    Folder could be empty.
    '''
    s3 = boto3.client('s3')
    path = path.rstrip('/') 
    resp = s3.list_objects(Bucket=bucket, Prefix=path, Delimiter='/',MaxKeys=1)
    return 'CommonPrefixes' in resp

• Observe it strips off the last / from path. This prefix will check just that folder and doesn't check within that folder.
• Observe it checks CommonPrefixes in response and not Contents

Answer 4

The following code should work...

import boto3
import botocore

def does_exist(bucket_name, folder_name):
    s3 = boto3.resource(
        service_name='s3',
        region_name='us-east-2',
        aws_access_key_id='********************',
        aws_secret_access_key='********************'
    )
    objects = s3.meta.client.list_objects_v2(Bucket=bucket_name, Delimiter='/', Prefix='')
    # print(objects)
    folders = objects['CommonPrefixes']

    folders_in_bucket = []
    for f in folders:
        print(f['Prefix'])
        folders_in_bucket.append(f['Prefix'])
    return folder_name in folders_in_bucket

print("does it exist?", does_exist('images-bucket','ddd/'))

As @Vinayak mentioned in one of the answer's comment in march, 2020...

The way to get a 'folder' list in boto3 is objects = s3.list_objects_v2(Bucket=BUCKET_NAME, Delimiter='/', Prefix='')

While running this with the latest versions of boto3 and botocore in August 2021 - '1.18.27', '1.21.27' respectively, gives the following error:

AttributeError: 's3.ServiceResource' object has no attribute 'list_objects_v2'

This happens since you are using s3 = s3.resource("mybucketname", credential-params) and s3.ServiceResource will not have s3.list_objects_v2() method. Instead, ServiceResource is having a meta attribute that will further have client type object from where you can apply Client object's methods on ServiceResource Object. like this - s3.meta.client.list_objects_v2()

Hope that helps!

Answer 5

import boto3
import botocore

client = boto3.client('s3')
def checkPath(file_path):
  result = client.list_objects(Bucket="Bucket", Prefix=file_path )
  exists=False
  if 'Contents' in result:
      exists=True
  return exists

if the provided file_path will exist then it will return True. example: 's3://bucket/dir1/dir2/dir3/file.txt' file_path: 'dir1/dir2' or 'dir1/' Note:- file path should start with the first directory just after the bucket name.

Answer 6

Basically a directory/file is S3 is an object. I have created a method for this (IsObjectExists) that returns True or False. If the directory/file doesn't exists, it won't go inside the loop and hence the method return False, else it will return True.

import boto3
s3 = boto3.resource('s3')
bucket = s3.Bucket('<givebucketnamehere>')

def IsObjectExists(path):
    for object_summary in bucket.objects.filter(Prefix=path):
        return True
    return False

if(IsObjectExists("<giveobjectnamehere>")):
   print("Directory/File exists")
else:
   print("Directory/File doesn't exists")

Note that if you are checking a folder, make sure that you end the string with / . One use case is that when you try to check for a folder called Hello and if the folder doesn't exist, rather there is a folder called Hello_World. In such case, method will return True. In this case you have to add / character to the end of folder name while coding. You can see how this is handled in the below example

foldername = "Hello/"
if(IsObjectExists(foldername))
    print("Directory/File exists")

Answer 7

Please try this code as following

Get subdirectory info folder¶

folders = bucket.list("","/")
for folder in folders:
    print (folder.name)

PS reference URL(How to use python script to copy files from one bucket to another bucket at the Amazon S3 with boto)