CODEWITHSUNDEEP
pythonlist
Alhpa Delta
Alhpa Delta

Reputation: 3660

Generate a list of names/strings randomly of desired size in python and add it to a dataframe column

I am tying to generate a random list of names from a given set. I have tried two different ways (group_1) and group_2 below, but both times I am not able to generate a list of names as desired. While group_1 makes each character into a separate element of the lsit, group_2 just makes a single element list. while i need list of 342 elemetns.

code:

import random
first_names=('John','mary','hillary')
last_names=('Johnson','Smith','Williams')

group_1=list(" ".join(random.choice(first_names)+" "+random.choice(last_names) for _ in range(342)))
group_2 = [" ".join(random.choice(first_names)+" "+random.choice(last_names) for _ in range(342))]

print(group_1)
print(len(group_1))
print(group_2)
print(len(group_2))

Upvotes: 0

Views: 58

Answers (2)

Jop Knoppers
Jop Knoppers

Reputation: 714

If I understand you correctly you want a list like the one shown below:

  • hillary Smith
  • mary Johnson
  • John Johnson
  • John Williams
  • hillary Smith
  • ......

This code will provide a list like that,

from random import randrange

first_names=('John','mary','hillary')
last_names=('Johnson','Smith','Williams')

names = [first_names[randrange(len(first_names))] + " " + last_names[randrange(len(last_names))] for _ in range(342)]
print (names)

Upvotes: 0

Djaouad
Djaouad

Reputation: 22776

The unnecessary " ".join is what's causing this problem, you can just omit it (since you already have + " " +) and use a list comprehension:

group = [random.choice(first_names) + " " + random.choice(last_names) for _ in range(342)]

print(len(group))
print(group)

Output:

342
['hillary Johnson', 'John Williams', 'John Johnson', 'mary Williams', 'mary Smith', ...]

Upvotes: 2

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