CODEWITHSUNDEEP
djangopython-3.x
parsap1378
parsap1378

Reputation: 55

writing Django custom model field

I want to write a custom field that shows size of an item. like: "small", "medium", "large", "extra large". It have to be optional like IntegerField. this is what I want it to be. I don't know where and what should I do.

Upvotes: 1

Views: 220

Answers (1)

willeM_ Van Onsem
willeM_ Van Onsem

Reputation: 476624

You do not need to define a custom Django model field for that. In fact Django already can handle that. You can provide a choices=… parameter [Django-doc] for that:

class SomeModel(models.Model):
    SIZE_CHOICES = (
        (1, 'small'),
        (2, 'medium'),
        (3, 'large'),
        (4, 'extra large'),
    )
    size = models.IntegerField(choices=SIZE_CHOICES)

In a ModelForm you can then use a RadioSelect widget [Django-doc] to select out of the choices:

class SomeForm(forms.ModelForm):

    class Meta:
        model = SomeModel
        fields = ('size',)
        widgets = {
            'size': forms.RadioSelect
        }

Upvotes: 2

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