CODEWITHSUNDEEP
pythonsyntax-errortry-catchtry-except
Spencer Bishop
Spencer Bishop

Reputation: 9

Using try statement, but giving me syntax error

Simple problem. I need to get the user to input a number, and then convert the string into an integer using try/except.

I've done things similar to this before. In fact I've done much more complicated things before, which is why I'm so confused as to why my code isn't working.

userNum = input('enter a number: ')
try:
    num = int(userNum)

For some reason this causes a syntax error. The error statement reads:

Syntax Error:     num = int(userNum): <string>, line 3, pos 23

Can anyone tell me why this would cause a problem and how I could fix it? I'm so confused.

Upvotes: 0

Views: 673

Answers (3)

kuco 23
kuco 23

Reputation: 830

Try needs to have at least one of the except or finally expressions followed as in:

userNum = input('enter a number: ')
try:
    num = int(userNum)
except ValueError as e:
    print(e)

Upvotes: 2

agtoever
agtoever

Reputation: 1699

In the syntax of a try statement, you can see that at least one except part or a finally part is obligatory.

Working code with except:

userNum = input('enter a number: ')
try:
    num = int(userNum)
except:
    print("you didn't enter a number")
print(num)

Try it online!

Upvotes: 1

developer_hatch
developer_hatch

Reputation: 16224

you can either use finally if you want something always happen, if you want something happen on error, use except:

userNum = input('enter a number: ')
try:
    num = int(userNum)
finally:
    print("something")

or:

userNum = input('enter a number: ')
try:
    num = int(userNum)
except Exception:
  print("exception something")
finally:
    print("something")

or:

userNum = input('enter a number: ')
try:
    num = int(userNum)
except Exception:
    print("exception something")

Upvotes: 2

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