CODEWITHSUNDEEP
pythonjsonpython-3.xunixfastjson
Sumit Bharati
Sumit Bharati

Reputation: 37

Is there a python equivalent to the Unix '$?' command?

I am using fastjsonschema for validating json records against its schema. Some thing like this:

import fastjsonschema
validate = fastjsonschema.compile({'type': 'string'})
validate('hello')

If the json is valid, it returns the json string else return the error string. I just want to check if the json is valid or not. For this I can do a workaround of comparing output of the validate method and the json input.

But I want something cleaner. May be something like '$?' in unix or something better.

Could you suggest me?

Upvotes: -2

Views: 271

Answers (1)

Judge
Judge

Reputation: 689

From the documentation, there seem to be two different exceptions thrown in case of error:

In Python, you can simply wrap that with a try ... except block like this:

try:
    validate = fastjsonschema.compile({'type': 'string'})
    validate(1)
except (fastjsonschema.JsonSchemaException, fastjsonschema.JsonSchemaDefinitionException):
    print("Uh oh ...")

Upvotes: 0

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