Reputation: 9317
I am new to Android WebView
, in my application i need to display a web site conatins 3 web pages. In the first web page there will be a link to navigate to the second page and second to third page. I given the URL in the WebView
, the first page is displayed perfectly, when i click the link it directly opens the browser application to display the second page. But i want to display the second page in the WebView
itself. Please find my code below:
WebView forumView=(WebView)findViewById(R.id.forumView);
forumView.getSettings().setJavaScriptEnabled(true);
forumView.loadUrl("url");
As i said i am very new to WebView
my code might be wrong, please help me to solve this problem.
Thanks in Advance, Rajapandian
Upvotes: 4
Views: 8479
Reputation: 17495
You'll have to intercept the clicks yourself if you don't want the default Android behavior.
You can monitor events in a WebView
using a WebViewClient
. The method you want is shouldOverrideUrlLoading()
. This allows you to perform your own action when a particular URL is selected.
You set the WebViewClient
of your WebView
using the setWebViewClient(
) method.
If you look at the WebView sample in the SDK there's an example which does just what you want. It's as simple as:
private class HelloWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
Upvotes: 3
Reputation: 6653
This piece of code will help you.
wbb = (WebView) findViewById(R.id.webView_tobe_loaded);
WebSettings wbset=wbb.getSettings();
wbset.setJavaScriptEnabled(true);
wbb.setWebViewClient(new MyWebViewClient());
String url="http://www.google.com";
System.out.println(getdeviceid());
wbb.getSettings().setJavaScriptEnabled(true);
wbb.loadUrl(url);
Upvotes: 4