Reputation: 145
I am using C++ 17 on a Windows 10 OS using a Visual Studio 2017 compiler.
I am trying to set up a menu system with do-while loops and user input (always a huge pain a year later). When I do these, I put an admonishment in an "else" statement if input was not of the correct type.
I ran this code thinking it would either die before it started or run perfectly, but got surprised when I entered the number 2 for the input in the itemMenu() function and got immediately kicked into that function's else statment. I did some debugging and confirmed that the if statements were all returning true. So how am I getting to the else statement instead?
I am using a lambda expression for the critical if statement and tested that the value of f, and in fact the if statement, is true. I do not regularly use these and I get weird notices about it during debug:
Menu.cpp
<...>\menu.cpp(94): warning C4805: '==': unsafe mix of type 'int' and type 'bool' in operation
<...>\menu.cpp(97): warning C4805: '==': unsafe mix of type 'int' and type 'bool' in operation
<...>\menu.cpp(86): warning C4715: '<lambda_6de01b1fefb73a14272db9ac7503c22b>::operator()': not all control paths return a value
<...>\Desktop\startingOver\Debug\startingOver.exe
That sounds like maybe my lambda expression is the problem, but more likely it is the cin flags needing to be cleared. I tried that too (perhaps incorrectly) and it did not solve the problem. What could be wrong? Here is my code:
//Menu.h
#pragma once
#include <iostream>
#include <string>
#include "Player.h"
#include "Item.h"
#include "MoveCommand.h"
using namespace std;
class Menu
{
public:
Menu();
~Menu();
static void mainMenu(Player * player);
static void itemMenu(Player * player);
static void hud(Player * player);
};
and
//Menu.cpp
#include "Menu.h"
Menu::Menu()
{
}
Menu::~Menu()
{
}
void Menu::mainMenu(Player * player)
{
char input;
// do and keep doing while input is bad
do {
cout << "What to do? (W: go north; S: go south; A: go west: D: go east; I: inventory ";
cin >> input;
if (toupper(input) == 'W')
{
MoveCommand * cmd = new MoveCommand(0, -1);
break;
}
else if (toupper(input) == 'S')
{
MoveCommand * cmd = new MoveCommand(0, 1);
break;
}
else if (toupper(input) == 'A')
{
MoveCommand * cmd = new MoveCommand(-1, 0);
break;
}
else if (toupper(input) == 'D')
{
MoveCommand * cmd = new MoveCommand(1, 0);
break;
}
else if (toupper(input) == 'I')
{
itemMenu(player);
break;
}
else {
cout << "Not an option, enter another input... " << endl;
system("pause");
}
system("CLS");
} while (toupper(input) != 'W' &&
toupper(input) != 'S' &&
toupper(input) != 'A' &&
toupper(input) != 'D' &&
toupper(input) != 'I');
system("cls");
}
void Menu::itemMenu(Player * player)
{
//All this first part does is draw a figure on the screen:
//----------------------------------------------
cout << "INVENTORY: " << endl;
for (int i = 0; i < 10; i++)
{
// if inventory location is null:
if (player->inventory[i], NULL) {
cout << "[ ]";
}
else
cout << "[ i ]";
}
cout << endl;
for (int i = 1; i <= 10; i++) cout << " " << i << " ";
cout << endl;
//------------------------------------------------
char input;
// I made this lambda function to facilitate the test the user input is a digit from 1 to 10.
// it is possible that this is a problem, even though debug says this value returns true (see note/test below)
auto f = [](char in) {for (int i = 1; i <= 10; i++) {
if (in == i) return true;
else
return false;
}};
// do and keep doing until choice is to quit
do {
cout << "Pick a slot: (Enter a number 1:10, or 'Q' to exit. ";
cin >> input;
if (toupper(input) == 'Q') break;
//bool both = (isdigit(input) == true && f(input) == true); // testing if value, which is true in debug tests...
// ... and yet we never see anything inside this block--I even did a pause, which works everywhere else, but
// the program is jumping to the else (wrong input) statment
if (isdigit(input) == true && f(input) == true) {
cout << "succesfully accessed " << input << "th inventory item" << endl;
system("pause");
}
else
cout << "(Inventory Else) Not an option, enter another input..." << endl; // I appended (Inventory Else) to confirm we go here
system("pause");
system("cls");
} while (toupper(input) != 'Q' && f(input) == false);
system("cls");
}
void Menu::hud(Player * player)
{
}
and
//Main.cpp
#pragma once
#include <iostream>
#include <string>
#include "Player.h"
#include "Command.h"
#include "MoveCommand.h"
#include "Event.h"
#include "Item.h"
#include "Tile.h"
#include "Menu.h"
int main() {
Player player;
//game loop
while (1) {
Menu::mainMenu(&player);
}
return 0;
}
EDIT: and I forgot this important piece of the puzzle:
//Player.h
class Player
{
private:
int _x;
int _y;
public:
Item *inventory[10];
Player();
//~Player();
//methods
int getX();
int getY();
void move(int x, int y);
};
Please note that if I am supposed to know a better way to do anything (like regex or try/throw/catch or anything else) I would rather if I were confident that I knew how.
Upvotes: 0
Views: 1740
Reputation: 179981
It appears that you are mixing 0
and '0'
. That is to say, the value 0 and the character 0. The first is an int
, the second is a char
. C++ will do some conversions, so '0'+2 == '2'
, but importantly '0'+'2' != '2'
.
Therefore, the loop in your lambda should run from char i = '0'
to i <= '9'
. Not that it really matters here. You missed out on std::isdigit(c)
.
Your other problem is isdigit(input) == true
. This is an anti-pattern. In C++, you don't compare against booleans. And it can fail spectacularly for isdigit(c)
, which returns a non-zero number when c
is a digit. It's very well possible that isdigit('5')
returns '5'
, and isdigit('0')
returns '0'
. Yes, I said a non-zero number, but '0'
is a non-zero number. isdigit('C')
will always return 0
(the number, not the character).
Upvotes: 3