CODEWITHSUNDEEP
node.jsasynchronous
user3277468
user3277468

Reputation: 141

Node Async Method Understanding

I have a method that I want to finish before any code after it can be ran but am lost in understand external links when is comes to this.

In one method I have the following code

var x = someMethod("1","2","3"); // Finish before anything below can be ran

The method itself is simple

function someMethod(x,y,z){
    if(1){
        return "sdfh"
    } else if(2){
        return "asdf"
    } else {
        return "ljkk"
    }
}

How can I retrieve x before continue the code below it. Ive seen examples of nested functions, await, async but am lost

Upvotes: 0

Views: 38

Answers (2)

David George Smith
David George Smith

Reputation: 134

Java script is single thread and synchronous. I recommend checking out JavaScript promises. However I would assume your code executes synchronously until it hits something like a AJAX that is asynchronous. check this answer out: When is JavaScript synchronous?.

Upvotes: 0

dyouberg
dyouberg

Reputation: 2332

Try: 

const someMethod = (x, y, z) => {
  ...
};

const otherMethod = async () => {
  let x = 'before value';
  console.log(`before someMethod x: ${x}`);
  // Finish before anything below can be ran
  x = await someMethod("1", "2", "3"); 
  console.log(`after someMethod x: ${x}`);
};

Basically you are defining the function which has the await call as an asynchronous function using the async keyword in the function declaration - and can signify the portion of the code which you would like to wait by prepending with await. There are nuances to this - but hopefully this helps.

Upvotes: 1

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