Reputation: 25
Now, I am facing with an error.
'Decision variables of type dvar float not supported by this algorithm.'
Here is the code that I made.
I will write it simply.
Firstly, I got in trouble with error that "'q1' is not convex."
So, now i am trying to 'Using CP;'
Using CP;
int a = 2;
int e = 4;
int h = 3;
int t = 6;
range arange = 1..a;
range erange = 1..e;
range hrange = 1..h;
range trange = 1..t;
int nd[erange][hrange] = [[0.8, 0.2, 0.3]
[0.3, 0.1, 0.6]
[0.1, 0.7, 0.5]];
dvar boolean x[arange][erange][trange];
dvar float y[erange][hrange][trange];
maximize
sum(a in arange, e in erange, h in hrange, t in trange)
y[e][h][t] * x[a][e][t];
subject to {
forall(a in arange, e in erange, t in trange, h in hrange)
y[e][h][t] == nd[e][h];
}
I need to use type of 'float' as a decision variable.
But 'Using CP;' does not support this type.
In this case, what should I do to solve this error.
Upvotes: 0
Views: 718
Reputation: 10062
as can be seen in the example floatexpr.mod you could use decision expressions in order to use decimal values. In your example:
using CP;
int a = 2;
int e = 4;
int h = 3;
int t = 6;
range arange = 1..a;
range erange = 1..e;
range hrange = 1..h;
range trange = 1..t;
float nd[erange][hrange] = [[0.8, 0.2, 0.3],
[0.3, 0.1, 0.6],
[0.1, 0.7, 0.5]];
int scale=10;
dvar boolean x[arange][erange][trange];
dvar int yscale[erange][hrange][trange] in 0..1000;
dexpr float y[a in erange][b in hrange][c in trange]=yscale[a][b][c]/scale;
maximize
sum(a in arange, e in erange, h in hrange, t in trange)
y[e][h][t] * x[a][e][t];
subject to {
forall(a in arange, e in erange, t in trange, h in hrange)
(y[e][h][t] - nd[e][h])<=0.01;
}
Upvotes: 1