CODEWITHSUNDEEP
flutterdart
Gudguy
Gudguy

Reputation: 1031

How to get n power ( square of a number or cube etc.) of a number in flutter?

I have two values one for base that is X and one for power N, how can a get X to the power of N ans.

any code will be appreciated.

Upvotes: 18

Views: 28329

Answers (5)

Vince Varga
Vince Varga

Reputation: 6958

Just as a reminder, when you are interested in the powers of two, you don't need the math library, and you can use bit manipulation and left shift:

1 << 0 // 1
1 << 1 // 2
1 << 2 // 4
// ...
1 << 5 // 32
// ...
1 << 10 // 1024

Upvotes: 3

ASFM Flayman
ASFM Flayman

Reputation: 1

void main()
{
int m, n;
  print("Enter 2 numbers: ");
  m = int.parse(stdin.readLineSync()!);
  n = int.parse(stdin.readLineSync()!);
  int power = 1;
  for (int i = 1; i <= n; i++) {
    power = power * m;
  }
  print(power);
}

Upvotes: 0

Suragch
Suragch

Reputation: 512346

For all of these examples with pow you need the following import:

import 'dart:math';

8²

final answer = pow(8, 2); // 64

Notes:

  • If you are only squaring, then it's probably easier to do this:

    final answer = 8 * 8;

  • answer is inferred to be of type num, which could be an int or double at runtime. In this case the runtime type is int, but in the following two examples it is double.

Fourth root of 256

final answer = pow(256, 1/4); // 4.0

0.2^(-3)

final answer = pow(0.2, -3); // 124.99999999999999

That's basically the same as five cubed.

Upvotes: 18

Gudguy
Gudguy

Reputation: 1031

btw Its working fine for double also

    double power() {
      double x= double.parse(t1.text);
      int y= int.parse(t2.text);
      double power = 1;
      for (double i = 0; i < y; i++) {
        power *= x;

      } ;


  return power;
}

Upvotes: 0

g_bor
g_bor

Reputation: 1092

You are looking for this: https://api.dartlang.org/stable/2.5.0/dart-math/pow.html so:

pow(X,N)

If you want to implement it, you can have a look at here: https://coflutter.com/challenges/dart-how-to-implement-exponential-function-power/ This boils down to this loop:

int power(int x, int n) {
  int retval = 1;
  for (int i = 0; i < n; i++) {
    retval *= x;
  }

  return retval;
}

This only works well for integer n-s.

Upvotes: 20

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