CODEWITHSUNDEEP
python-3.xstringcharacter
inarisound inarisound
inarisound inarisound

Reputation: 69

Is there any 'native' method that can give information about a character in the string?

I want to check a character in the string if it's a number, space, upper/lower character or a special character ".'*^?..."

I came up with the solution that is not very slick, plus it can't check for special characters without adding extra lines in else statement. 

def checker(str1):
if str1.isspace() is True:
    print('it\'s a space')
if str1.isupper() is True:
    print('it\'s a letter and it\'s upper')
if str1.islower() is True:
    print('it\'s a letter and it\'s lower')
if str1.isdigit() is True:
    print('it\'s a digit')
if str1.isascii() is True:
    print('it\'s a special chracter')

string_letter = 'A'

checker(string_letter)

this code works... if I create some extra clause for special characters because right now it's just saying that space is a special character... it happens because .isascii() just too broad for special characters.

Is there any native method that I miss that can do that functionality more elegantly? aka give information on a character in the string?

I am very new to python, so I'm sorry, maybe I was not able to find native solution because I am not very fluent in terminology yet.

Upvotes: 1

Views: 28

Answers (1)

Lamanus
Lamanus

Reputation: 13551

Use elif and place the special character checker to the last.

def checker(str1):
    if str1.isspace():
        print('it\'s a space')
    elif str1.isupper():
        print('it\'s a letter and it\'s upper')
    elif str1.islower():
        print('it\'s a letter and it\'s lower')
    elif str1.isdigit():
        print('it\'s a digit')
    elif str1.isascii():
        print('it\'s a special chracter')

string_letter = '&'

checker(string_letter)

Then, 

it's a special chracter

Upvotes: 1

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