CODEWITHSUNDEEP
jsonspring-boot
Darkly
Darkly

Reputation: 395

Deserialize just one or two attributes from a Json in Spring Boot

So in this case, I want to consume a third party API to compare capitals with countries, I don't need any other attribute from the Json but those 2, however the API I'm using has a lot of extra attributes on it.

What is the easiest way to deserialize the Json into a class with just those 2 attributes I want?

I tried this but of course it didn't work: 

        Country country = restTemplate.getForObject( "https://restcountries.eu/rest/v2/capital/"+learning.getCapital(), Country.class);

I understand that this doesn't work because it's trying to map the Json attributes into the class which of course lacks the remaining attributes (It just has two string attributes called Name and Capital).

Upvotes: 0

Views: 866

Answers (3)

Toerktumlare
Toerktumlare

Reputation: 14712

if you want this feature globally you can set in your application.properties

spring.jackson.deserialization.FAIL_ON_UNKNOWN_PROPERTIES=false

Upvotes: 1

Puce
Puce

Reputation: 38132

Annotate the class with @JsonIgnoreProperties:

@JsonIgnoreProperties(ignoreUnknown = true)
public class Country {

Upvotes: 1

i.bondarenko
i.bondarenko

Reputation: 3572

You could ignore unkown properties on object mapper for this rest template:

 objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);

Upvotes: 1

Related Questions