CODEWITHSUNDEEP
functionjulia
logankilpatrick
logankilpatrick

Reputation: 14521

How to write a function in Julia that accepts a variable number of arguments?

I am trying to write a function that should be allowed to take in a variable number of arguments. However, it's not too clear how I can do that in Julia.

Upvotes: 4

Views: 6038

Answers (1)

logankilpatrick
logankilpatrick

Reputation: 14521

In Julia, as with many other languages, there exists the ability to write Vararg Functions. These functions allow for a variable number of arguments to be passed in. Here a quick reference to the Julia docs on this idea and an example: 

julia> varargs(a,b,c...) = (a,b,c)
varargs (generic function with 1 method)

julia> varargs(5, 10)
(5, 10, ())

julia> varargs(3,4,5)
(3, 4, (5,))

julia> varargs(10, 20, 30, 40, 50, 60, 70, 80)
(10, 20, (30, 40, 50, 60, 70, 80))

julia> d = (2,3,4,5,6,7,8,9)
(2, 3, 4, 5, 6, 7, 8, 9)

julia> varargs(1,2,d)
(1, 2, ((2, 3, 4, 5, 6, 7, 8, 9),))

To reiterate, the magic is happening here when we define the varargs function and write c.... This notation enables the whole concept of variable-sized arguments.

Upvotes: 5

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