CODEWITHSUNDEEP
pythonseleniumxpathcss-selectorswebdriverwait
fairy starlight
fairy starlight

Reputation: 49

How to click on the tab button using Selenium Webdriver and Python

I will click that button in red circle.enter image description here

and I would like to crawling that site. How do I write python codes?

I tried this code and

from bs4 import BeautifulSoup
from urllib.request import urlopen
import time
from selenium import webdriver 
driver = webdriver.Chrome('./chromedriver.exe')
url_base = 'https://www.kebhana.com/cont/mall/mall08/mall0805/index.jsp?_menuNo=62608'
driver.implicitly_wait(5)

driver.get(url_base)
openElement = driver.findElement(By.linkText("li[2]")).click(); 


time.sleep(2)

openElement.click()
time.sleep(5)


driver.quit()
soup

the error message were appeared like this:

AttributeError                            Traceback (most recent call last)
<ipython-input-16-19b58965022a> in <module>()
      8 
      9 driver.get(url_base)
---> 10 openElement = driver.findElement(By.linkText("li[2]")).click();
     11 
     12 

AttributeError: 'WebDriver' object has no attribute 'findElement'

and the html code of that button is

<li class="on">
   <a href="#none" onclick="javascript:doTab('spb_2812');">
      <span>적 금</span>
   </a>
</li>

Upvotes: 0

Views: 3935

Answers (3)

undetected Selenium
undetected Selenium

Reputation: 193108

You need to take care of a couple of things:

  • As you are using Selenium-Python clients, findElement() is not a valid line of code. Instead you need to use either of the following:

    • find_element_by_xpath()
    • find_element_by_css_selector()

  • linkText accepts only text only.

  • Inducing time.sleep(5) will degrade the Test Execution performance.

Solution

To click() on the element with text as 적 금, you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:

  • CSS_SELECTOR:

    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "ul.productSearchDiv li:nth-child(2) >a>span"))).click()

  • XPATH:

    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//ul[@class='productSearchDiv ']//li/a/span[text()='적 금']"))).click()

  • Note : You have to add the following imports :

    from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

  • Browser Snapshot:

kebhana

Upvotes: 1

Guy
Guy

Reputation: 50864

findElement is Java syntax, not Python. In addition, li is a tag, not text, and by_link_text doesn't work on <span> tags anyway.

Use xpath instead

driver.find_element_by_xpath('//li[.//span[.="적 금"]]')

Upvotes: 0

KunduK
KunduK

Reputation: 33384

To click on the tab you need to induce WebDriverWait and element_to_be_clickable() and use below xapth.

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium import webdriver

driver=webdriver.Chrome('./chromedriver.exe')
driver.get("https://www.kebhana.com/cont/mall/mall08/mall0805/index.jsp?_menuNo=62608")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[@class='productSDiv']//li//a[contains(@onclick,'spb_2812')]"))).click()

Upvotes: 0

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