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regexlinuxbashshellgrep
HotWheels
HotWheels

Reputation: 444

Counting number of words that contain a substring with grep

I am trying to grep a file for the words that contain "owner" but not the word owner itself. So, "ownership" for example would be counted.

I know: 

grep -o -c owner  #Print only matched words.  ship(owner)ship --> owner

grep -w -c owner #Match only whole words. ownership (No), owner (Yes)

But it returns the whole standalone word "owner" still.

Whats the correct way to do this?

Upvotes: 0

Views: 159

Answers (1)

karakfa
karakfa

Reputation: 67567

try this

grep -Pc '(\wowner)|(owner\w)' file

the word should have either a prefix or suffix (so the standalone won't match). Note that this will count the number of lines that have a match. To count the occurances

grep -oP '(\wowner)|(owner\w)' file | wc -l

Upvotes: 1

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