CODEWITHSUNDEEP
nosqlgremlinjanusgraphgremlin-server
ibt23sec5
ibt23sec5

Reputation: 407

Get all vertices with a specific property, label and id along the path

I have following structure in a Janusgraph database:

gremlin> continent = g.addV("continent").property("name", "Europe").next()
gremlin> country = g.addV("country").property("name", "France").next()
gremlin> region = g.addV("region").property("name", "Ile-de-France").next()
gremlin> departement = g.addV("departement").property("name", "Hauts-de-Seine").next()
gremlin> city = g.addV("city").property("name", "Saint-Cloud").next()
gremlin> g.V(continent).addE('is_part_of').to(country).iterate()
gremlin> g.V(country).addE('is_part_of').to(region).iterate()
gremlin> g.V(region).addE('is_part_of').to(departement).iterate()
gremlin> g.V(departement).addE('is_part_of').to(city).iterate()

I did to get the property name from all vertices from city to continent from the following query:

gremlin> g.V(city).emit().repeat(inE("is_part_of").outV().simplePath()).path().unfold().dedup().values("name")
==>Saint-Cloud
==>Hauts-de-Seine
==>Ile-de-France
==>France
==>Europe

But I would like to get also the id and the label of every returned vertex. I tried to use valueMap(true) instead of values("name") step to get all properties including id and label, but big part of vertices contain lot of properties which could be heavy in the level of performance. Is it possible to get those values from each vertex?

Upvotes: 3

Views: 474

Answers (1)

stephen mallette
stephen mallette

Reputation: 46206

You could just do valueMap(true, 'name')

gremlin> g.V(city).emit().repeat(inE("is_part_of").outV().simplePath()).
......1>   path().
......2>   unfold().
......3>   dedup().
......4>   valueMap(true,'name')
==>[id:8,label:city,name:[Saint-Cloud]]
==>[id:13,label:is_part_of]
==>[id:6,label:departement,name:[Hauts-de-Seine]]
==>[id:12,label:is_part_of]
==>[id:4,label:region,name:[Ile-de-France]]
==>[id:11,label:is_part_of]
==>[id:2,label:country,name:[France]]
==>[id:10,label:is_part_of]
==>[id:0,label:continent,name:[Europe]]

Upvotes: 3

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