CODEWITHSUNDEEP
javascript
None
None

Reputation: 9247

Substring between two strings?

var str = "https://cdn.fbsbx.com/v/t59.2708-21/68856895_411975049700005_8580443955521388544_n.xls/test.xls?_nc_cat=106&_nc_oc=AQmcm2PVCUFFyUJDJgLs3ZYM4Dg12PX1Wv48Fm0LJ8-Qi8duxOpEVrD2uFgrD9e1pDOXcLpJmbtjbveAm12xczd2&_nc_ht=cdn.fbsbx.com&oh=18eab18ae1d1cf2a95084bba0a002163&oe=5D8F8124";
var n = str.substring(str.indexOf("\\.") +1 , str.indexOf("?_nc_cat="));

I have this string but my output is :

https://cdn.fbsbx.com/v/t59.2708-21/68856895_411975049700005_8580443955521388544_n.xls/test.xls

How can i get only this .xls?

My other string is :

https://scontent.xx.fbcdn.net/v/t1.15752-9/70629455_2730574856953299_3640328874664919040_n.png?_nc_cat=100&_nc_oc=AQm0m5jryh7zAzyj2R-w7ke0DKQgHM7aYaVkkRjPYDUQ6g-FUAWqVwhnr7qxqISkWMdiNhtp7e8gYMA6gss58poN&_nc_ad=z-m&_nc_cid=0&_nc_zor=9&_nc_ht=scontent.xx&oh=1cbb98fb9484bd3f26b6058808cca889&oe=5E36459B

but again im not getting just word "png" im getting from start link.

Upvotes: 1

Views: 72

Answers (3)

Code Maniac
Code Maniac

Reputation: 37775

Since it seems you're trying to get the last value from pathname which is preceded by . from URL, so you can use URL API

Simply parse the URL with URL api, take the patname value and split on . and take the last element from splitted array.

var str = "https://cdn.fbsbx.com/v/t59.2708-21/68856895_411975049700005_8580443955521388544_n.xls/test.xls?_nc_cat=106&_nc_oc=AQmcm2PVCUFFyUJDJgLs3ZYM4Dg12PX1Wv48Fm0LJ8-Qi8duxOpEVrD2uFgrD9e1pDOXcLpJmbtjbveAm12xczd2&_nc_ht=cdn.fbsbx.com&oh=18eab18ae1d1cf2a95084bba0a002163&oe=5D8F8124";

let valueExtractor = (str) =>{
  let urlParse = new URL(str)
  return urlParse.pathname.split('.').pop()
}


console.log(valueExtractor(str))
console.log(valueExtractor("https://cdn.fbsbx.com/v/t59.2708-21/68856895_411975049700005_8580443955521388544_n.xls/test.png?_nc_cat=106&_nc_oc=AQmcm2PVCUFFyUJDJgLs3ZYM4Dg12PX1Wv48Fm0LJ8-Qi8duxOpEVrD2uFgrD9e1pDOXcLpJmbtjbveAm12xczd2&_nc_ht=cdn.fbsbx.com&oh=18eab18ae1d1cf2a95084bba0a002163&oe=5D8F8124"))

Upvotes: 0

Sreeram Nair
Sreeram Nair

Reputation: 2393

Simply, Just you have to use the LastIndexof() in the right way to achieve this

str = "https://scontent.xx.fbcdn.net/v/t1.15752-9/70629455_2730574856953299_3640328874664919040_n.png?_nc_cat=100&_nc_oc=AQm0m5jryh7zAzyj2R-w7ke0DKQgHM7aYaVkkRjPYDUQ6g-FUAWqVwhnr7qxqISkWMdiNhtp7e8gYMA6gss58poN&_nc_ad=z-m&_nc_cid=0&_nc_zor=9&_nc_ht=scontent.xx&oh=1cbb98fb9484bd3f26b6058808cca889&oe=5E36459B";
url = str.substring(0,str.indexOf("?"));
ext = str.substring(url.lastIndexOf(".")+1, url.length);

The same will work for any other string as well.

Upvotes: 0

CertainPerformance
CertainPerformance

Reputation: 371193

I'd use a regular expression, and match word characters while looking ahead for ?:

const getFileType = str => str.match(/\w+(?=\?)/)[0];

console.log(getFileType("https://cdn.fbsbx.com/v/t59.2708-21/68856895_411975049700005_8580443955521388544_n.xls/test.xls?_nc_cat=106&_nc_oc=AQmcm2PVCUFFyUJDJgLs3ZYM4Dg12PX1Wv48Fm0LJ8-Qi8duxOpEVrD2uFgrD9e1pDOXcLpJmbtjbveAm12xczd2&_nc_ht=cdn.fbsbx.com&oh=18eab18ae1d1cf2a95084bba0a002163&oe=5D8F8124"));

console.log(getFileType('https://scontent.xx.fbcdn.net/v/t1.15752-9/70629455_2730574856953299_3640328874664919040_n.png?_nc_cat=100&_nc_oc=AQm0m5jryh7zAzyj2R-w7ke0DKQgHM7aYaVkkRjPYDUQ6g-FUAWqVwhnr7qxqISkWMdiNhtp7e8gYMA6gss58poN&_nc_ad=z-m&_nc_cid=0&_nc_zor=9&_nc_ht=scontent.xx&oh=1cbb98fb9484bd3f26b6058808cca889&oe=5E36459B'));

Upvotes: 1

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