CODEWITHSUNDEEP
c
user10037397
user10037397

Reputation:

Printing Linked Lists

Im trying to print variables that assigned in the nodes but it prints random data.

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>

struct Node{
    int data;
    struct Node * next;
};

int main()
{
    struct Node* head = NULL;
    struct Node* second = NULL;
    struct Node* third = NULL;

    head = (struct Node*)malloc(sizeof(struct Node));
    second = (struct Node*)malloc(sizeof(struct Node));
    third = (struct Node*)malloc(sizeof(struct Node));

    head -> data = 1;
    head -> next = second;

    second -> data = 2;
    second -> next = third;

    third-> data = 3;
    third -> next = NULL;


    printf("%d",head);
    printf("\n%d",second); //problem in this part
    printf("\n%d",third);




    return 0;

I'm expecting an output like 1,2,3 which are variables that I assigned to.

Upvotes: 0

Views: 39

Answers (1)

sephiroth
sephiroth

Reputation: 906

You are printing the pointer, i.e. the address of those structures. if you want to print data you should print the data field:

printf("%d", head->data);

also, if you want to print out all the elements of a singly linked list, you can do this:

struct Node* p = head;
while (p != NULL)
{
  printf("%d\n", p->data);
  p = p->next;
}

Upvotes: 1

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