Reputation: 713
I am trying to parse the below json but unable to do that as stack over flow error comes in.
Here is the JSON -
[{
"Class": "1",
"school": "test",
"description": "test",
"student": [
"Student1",
"Student2"
],
"qualify": true,
"annualFee": 3.00
}]
Here is the code which is failing currently.
String res = cspResponse.prettyPrint();
org.json.JSONObject obj = new org.json.JSONObject(res);
org.json.JSONArray arr = obj.getJSONArray(arrayName);
String dataStatus=null;
for (int i = 0; i < arr.length(); i++) {
dataStatus = arr.getJSONObject(i).getString(key);
System.out.println("dataStatus is \t" + dataStatus);
}
Usecases are:
I appreciate your help.
update-1 Code more info on stack trace updated with below details. cls = 1
error- org.json.JSONException: JSONObject["student "] not a string.
Stack trace-
public String getString(String key) throws JSONException {
Object object = this.get(key);
if (object instanceof String) {
return (String) object;
}
throw new JSONException("JSONObject[" + quote(key) + "] not a string.");
}
When I ran the code with the below answers, here its failing for student is not a string.
The answers I used from first two comments and both have the same error. I appropriate your help.
Upvotes: 1
Views: 5554
Reputation: 874
Your JSON reponse root is array but you consider your JSON response as JSON object
Changing your parsing json code as below
String res=cspResponse.prettyPrint();
org.json.JSONArray arr = new org.json.JSONArray(res);
String dataStatus=null;
for (int i = 0; i < arr.length(); i++) {
org.json.JSONObject obj=arr.getJSONObject(i);
dataStatus = obj.getString(key);
System.out.println("dataStatus is \t" + dataStatus);
String schoolName = org.getString("school");
System.out.println("school => " + schoolName);
org.json.JSONArray students = obj.getJSONArray("student");
System.out.println("student[0] = " + students.get(0));
System.out.println("student[1] = " + students.get(1));
}
Upvotes: 1
Reputation: 16
You can use simple JSONObject class and Simple JSONParser for parsing the JSON.
1. Parse the JSON.
org.json.simple.JSONParser parser = new org.json.simple.JSONParser();
org.json.simple.JSONObject parsedJSON = parser.parse(inputJSON);
2. To get class:
String class = parsedJSON.get("Class");
3. To get Students:
org.json.simple.JSONArray studentArray = parsedJSON.get("student");
4. To Get School:
String school = parsedJSON.get("school");
After the above steps, you can run a for-loop to print the class and students.
Upvotes: 0
Reputation: 1090
Your json fragment is invalid - the last comma breaks the parsing. But the rest of the code is quite workable.
String res = "[\n" +
" {\n" +
" \"Class\": \"1\",\n" +
" \"school\": \"test\",\n" +
" \"description\": \"test\",\n" +
" \"student\": [\n" +
" \"Student1\",\n" +
" \"Student2\"\n" +
" ],\n" +
" \"qualify\": true,\n" +
" \"annualFee\": 3.00\n" +
" }\n" +
"]";
JSONArray arr = new JSONArray(res);
for (int i = 0; i < arr.length(); i++) {
JSONObject block = arr.getJSONObject(i);
Integer cls = block.getInt("Class");
System.out.println("cls = " + cls);
Object school = block.getString("school");
System.out.println("school = " + school);
JSONArray students = block.getJSONArray("student");
System.out.println("student[0] = " + students.get(0));
System.out.println("student[1] = " + students.get(1));
}
should output
cls = 1
school = test
student[0] = Student1
student[1] = Student2
Upvotes: 2