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pythonfunctionsvgparametersarguments
Clement08
Clement08

Reputation: 15

Python : call a function with n arguments

I'm using a function from the drawSVG library: draw.Lines(). This function is drawing lines between specified points. For example, draw.Lines(x0, y0, x1, y1) draw a line between the point (x0, y0) and (x1, y1).

My problem is that I would like to draw n lines. To do that, I need to call the function with n arguments (draw.Lines(x0, y1, ... xn, yn)). Each argument must be a number. I have tried using lists and it didn't work.

I didn't find a way to do it properly. Right now I'm calling the function with the right amount of arguments but I do not like that.

For example if I want to print a square

svg.append(draw.Lines(10,10,100,10,100,100,10,100))

Upvotes: 1

Views: 148

Answers (1)

rdas
rdas

Reputation: 21275

You can use argument unwrapping to pass a list to a function which expects multiple positional arguments.

Your example can be re-written as:

points = [10,10,100,10,100,100,10,100]
svg.append(draw.Lines(*points))

So if you have the end-coordinates for your n lines in a list, you can pass that (with a *) to the drawLines function.

Upvotes: 2

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