CODEWITHSUNDEEP
c
Rajesh Chukka
Rajesh Chukka

Reputation: 13

Hexadecimal array in pointer

 # include <stdio.h>
 int main()
 {
    char p[]={0x01,0x02,0x03,0x04};
    int *q = p;
    printf("%x",*q);
    return 0;

  }

When I run the above code, the answer is 4030201. Why?

Upvotes: 0

Views: 376

Answers (1)

Alexander Ushakov
Alexander Ushakov

Reputation: 5407

It is because you compile and run your code on little-endian architecture machine (x86 for example)

At first you put 4 bytes in memory in order: 01 02 03 04. Than convert pointer to this array to pointer to int. On little-endian machine memory block 01 02 03 04 represents integer value 0x04030201 which is printed on next step.

See https://en.m.wikipedia.org/wiki/Endianness for more information

Upvotes: 1

Related Questions