CODEWITHSUNDEEP
pythonpython-3.x
Bret
Bret

Reputation: 81

For Loops with Lists

def divisible_by_7(lst: List[int]) -> bool:
    """Return True if and only if lst contains an element divisible
    by 7. Otherwise, return False.

    >>> divisible_by_7([4,8,21,6])
    True
    >>> divisible_by_7([1,2,8,9])
    False
    """
    for num in lst:
        if num % 7 == 0:
            return True
        return False

When I run this function, it will only execute once. How can I instead verify all values in the list and see if they are True or False so it properly follows how for loops function without using the built-in any function?

Upvotes: 0

Views: 1962

Answers (3)

bharatk
bharatk

Reputation: 4315

Use for-else loop

Ex.

def divisible_by_7(lst: list) -> bool:
    for num in lst:
        if num % 7 == 0:
            return True
    else:
        return False

lst = [4,8,21,6]
lst1 = [1,2,8,9]
print(divisible_by_7(lst))
print(divisible_by_7(lst1))

True
False

Upvotes: 1

haminlee
haminlee

Reputation: 21

    def divisible_by_7(self, lst):
        """Return True if and only if lst contains an element divisible
        by 7. Otherwise, return False.

        >>> divisible_by_7([4,8,21,6])
        True
        >>> divisible_by_7([1,2,8,9])
        False
        """
        for num in lst:
            if num % 7 == 0:
                return True
        return False

Put your return False statement outside of the for-loop. Return True iff there is an element in the list that is divisible by 7 and return False as default.

Upvotes: 2

null
null

Reputation: 2137

Since there is no if check for return False if it grabs no if num % 7 == 0 it returns False in any iteration, you should dedent return False as @jonrsharpe commented. Yet, you can have the following code.

Code

def divisible_by_7(lst: list) -> bool:
    """Return True if and only if lst contains an element divisible
    by 7. Otherwise, return False.

    >>> divisible_by_7([4,8,21,6])
    True
    >>> divisible_by_7([1,2,8,9])
    False
    """
    return any([num%7 == 0 for num in lst])

Output

>>> divisible_by_7([4,8,21,6])
True
>>> divisible_by_7([1,2,8,9])
False

Upvotes: 1

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