CODEWITHSUNDEEP
pythongeometry
Selman
Selman

Reputation: 83

How to divide a rectangle in specific number of rows and columns?

I am trying to divide a rectangle with specific coordinates into 8 smaller rectangles (two columns and four rows) is this possible?

Input for example would be:

rec = [(0, 0), (0, 330), (200, 330), (200, 0)]

and result would be:

res = [[(0, 0), (0, 82), (100, 82), (100, 0)], [(0, 82), (0, 164), (100, 164), (100, 82)],.......]

This is what I've tried so far:

h = 330
w = 200

offsets = [(0, 0), (400, 0), (0, 500), (400, 500)]

blisters = []

for offset in offsets:
    pol = [(offset), (offset[0], offset[1] + h), (offset[0] + w, offset[1] + h), (offset[0] + w, offset[1])]
    blisters.append(pol)

pits = []

for offset in offsets:
    pit = [(offset), (offset[0], int(offset[1] + a)), (int(offset[0] + b), int(offset[1] + a)), (int(offset[0] + b), offset[1]), ]
    pits.append(pit)

This is what I need (kind of :/):

starting point in upper left corner (eg.(0,0)) 
                         ___________
                         I    I    I
                         I    I    I
                         -----------
                         I    I    I
                         I    I    I
                         -----------
                         I    I    I
                         I    I    I
                         -----------
                         I    I    I
                         I    I    I
                         -----------

Upvotes: 8

Views: 2830

Answers (3)

GV_FiQst
GV_FiQst

Reputation: 1567

Welcome to StackOverflow!

It's pretty simple. Just divide your boundaries on your columns and rows and then iterate over them:

cols, rows = 2, 4
width, height = 200.0, 330.0

w = width / cols
h = height / rows

result = []
for c in range(cols + 1):
    for r in range(rows + 1):
        result.append((c * w, r * h))

print result

# [(0.0, 0.0), (0.0, 82.5), (0.0, 165.0), (0.0, 247.5), (0.0, 330.0), 
# (100.0, 0.0), (100.0, 82.5), (100.0, 165.0), (100.0, 247.5), 
# (100.0, 330.0), (200.0, 0.0), (200.0, 82.5), (200.0, 165.0), 
# (200.0, 247.5), (200.0, 330.0)]

Upvotes: 0

Georgy
Georgy

Reputation: 13697

If you work a lot with geometric objects you might consider using Shapely library. It has some useful functionality that we could use in order to construct a grid of smaller rectangles from the given rectangle.

First, constructing a Polygon from your list of tuples:

from shapely.geometry import LineString, MultiPolygon, Polygon
from shapely.ops import split

rec = [(0, 0), (0, 330), (200, 330), (200, 0)]
nx, ny = 2, 4  # number of columns and rows

polygon = Polygon(rec)

This is your polygon:
enter image description here

Next, constructing a list of lines that we will use to split that polygon:

minx, miny, maxx, maxy = polygon.bounds
dx = (maxx - minx) / nx  # width of a small part
dy = (maxy - miny) / ny  # height of a small part
horizontal_splitters = [LineString([(minx, miny + i*dy), (maxx, miny + i*dy)]) for i in range(ny)]
vertical_splitters = [LineString([(minx + i*dx, miny), (minx + i*dx, maxy)]) for i in range(nx)]
splitters = horizontal_splitters + vertical_splitters

Applying each line to split the polygon:

result = polygon
for splitter in splitters:
    result = MultiPolygon(split(result, splitter))

This is how your resulting collection of rectangles will look like:
enter image description here

If you want a list of coordinates back, you can get them like this:

parts = [list(part.exterior.coords) for part in result.geoms]
print(parts)
# [[(0.0, 0.0), (0.0, 82.5), (100.0, 82.5), (100.0, 0.0), (0.0, 0.0)],
#  [(100.0, 82.5), (200.0, 82.5), (200.0, 0.0), (100.0, 0.0), (100.0, 82.5)],
#  [(0.0, 82.5), (0.0, 165.0), (100.0, 165.0), (100.0, 82.5), (0.0, 82.5)],
#  [(100.0, 165.0), (200.0, 165.0), (200.0, 82.5), (100.0, 82.5), (100.0, 165.0)],
#  [(0.0, 165.0), (0.0, 247.5), (100.0, 247.5), (100.0, 165.0), (0.0, 165.0)],
#  [(100.0, 247.5), (200.0, 247.5), (200.0, 165.0), (100.0, 165.0), (100.0, 247.5)],
#  [(0.0, 247.5), (0.0, 330.0), (100.0, 330.0), (100.0, 247.5), (0.0, 247.5)],
#  [(100.0, 330.0), (200.0, 330.0), (200.0, 247.5), (100.0, 247.5), (100.0, 330.0)]]

Upvotes: 6

wgb22
wgb22

Reputation: 247

If you use the numpy library, the problem is greatly simplified using the linspace function which generates equally-spaced points.

import numpy as np

h = 330
n_rows = 4

w = 200
n_cols = 2

offset_x = w / n_cols
offset_y = h / n_rows

rectangles = []
for x in np.linspace(0, w, n_cols+1).tolist()[:-1]:
    for y in np.linspace(0, h, n_rows+1).tolist()[:-1]:
        x1 = int(round(x))
        x2 = int(round(x + offset_x))
        y1 = int(round(y))
        y2 = int(round(y + offset_y))
        rectangles.append([(x1, y1), (x1, y2), (x2, y2), (x2, y1)])

print(rectangles)

Upvotes: 3

Related Questions