CODEWITHSUNDEEP
phpsmarty
user7693832
user7693832

Reputation: 6849

How can I in smarty get a array's special name's value?

I have a PHP array like below:

$list = array(
    array(
        'name'=>'switch',
        'value'=>'cisco'
    ),
    array(
        'name'=>'switchport',
        'value'=>'2'
    )
);

How can I get name='switch' or name='switchport''s item in one step?

because this is in smarty template, there is the img

<img src="http://localhost:8080/api.php?switch={$my_need_switch_value}&switchport={$my_need_switchport_value}">

So, how can I get the my_need_switch_value from $list in one step?

Upvotes: 0

Views: 69

Answers (4)

aircraft
aircraft

Reputation: 26896

You can use {assign} to assign new variables.

{foreach from=$list item=customfield}
    {if $customfield.name=='switch'}
        {assign var=switch value=$customfield.value}
    {elseif $customfield.name=='switchport'}
        {assign var=portname value=$customfield.value}
    {/if}

{/foreach}

then you can use the $switch and $switchport directily.

Upvotes: 1

Lucas Arbex
Lucas Arbex

Reputation: 909

If I understood correctly what you want, you can create a function with the array and the name you want to find as parameters, then loop through it and get its value. Like so:

$list = [
    [
        'name'=>'switch',
        'value'=>'cisco'
    ],
    [
        'name'=>'switchport',
        'value'=>'2'
    ]
];

function getValue($array, $name) {
    foreach($array as $key => $value) {
        if($value['name'] == $name) {
            echo $value['value'];
        }
    }
}

If you call it using 'switch' as name parameter it will echo 'cisco', and if you change it to 'switchport', it will echo '2'. Then you can use it on your structure like so:

<img src="http://localhost:8080/api.php?switch={getValue($list,'switch')}&switchport={getValue($list,'switchport')}">

Is that what you want to achieve?

Upvotes: 0

Stefano Maglione
Stefano Maglione

Reputation: 4150

Have you tried something like:

$list[0].name
$list[1].name

I do not believe there is a one shoot. You should at least iterate the array and compare the value with what you need.

Upvotes: 0

zeljko miloradovic
zeljko miloradovic

Reputation: 71

Did you try {$list.0} or {$list.0.name}? If I understood what you want.

Upvotes: 0

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