CODEWITHSUNDEEP
python
jparanich
jparanich

Reputation: 9024

Python datetime subtraction while ignoring weekend days

I'm familiar with the timedelta method in Python for subtracting days from the current date (below); however I'm curious how I could go about getting it to automatically skip over weekends.

from datetime import datetime, timedelta
target_date = datetime.today() - timedelta(days=dayoffset)

So for example, 2019-Oct-08 less 3 days would be 2019-Oct-03 (as the 5th and 6th are weekend days). Thank you!

Upvotes: 0

Views: 1308

Answers (1)

Lê Tư Thành
Lê Tư Thành

Reputation: 1083

You can try datetime.weekday(), it returns date to a value from 0-6, while 5 and 6 are the weekend days.

Read more on this.

from datetime import datetime, timedelta
def diff_day(start, end):
    delta = timedelta(days=1)
    d = start
    diff = 0
    weekend = [5, 6]
    while d < end:
        if d.weekday() not in weekend:
            diff += 1
        d += delta
    return diff

>>>start = datetime(2019,10,3)
>>>end = datetime(2019,10,8)
>>>diff_day(start, end)
3

Upvotes: 2

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