CODEWITHSUNDEEP
pythondjangodjango-modelsdjango-rest-frameworkdjango-views
MGassend
MGassend

Reputation: 103

How to partiallly update a model in django rest framework?

I built an api with django and I have a picture model that comprises an imagefield. I'm trying to perform a partial update

I already tried setting partial = Trueto the Serializer's definition

the serializer is

class PictureSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = Picture
        fields = ("id", "name", "picture", "button_1", "button_2", "button_3", "button_4")
        partial = True

the model is

class Picture(models.Model):
    name = models.CharField(max_length=250)
    picture = models.ImageField(upload_to="pictures/", null=True, blank=True)
    button_1 = models.BooleanField(default=False)
    button_2 = models.BooleanField(default=False)
    button_3 = models.BooleanField(default=False)
    button_4 = models.BooleanField(default=False)
    printed = models.IntegerField(default=0)

the view is

class PictureViewSet(viewsets.ModelViewSet):
    queryset = Picture.objects.all()
    serializer_class = PictureSerializer

Upvotes: 0

Views: 123

Answers (1)

Toni Sredanović
Toni Sredanović

Reputation: 2412

Expose your ViewSetin urls.py:

router = routers.DefaultRouter()
router.register(r'pictures', PictureViewSet, base_name='picture')

urlpatterns = [
    url(r'', include(router.urls)),
]

Send PATCH request with JSON data you want to update to the exposed endpoint. Mind that PATCH requests go to instance endpoint of the instance you want to update so your URL will look like this: .../pictures/<picture_id>.

{
  "name": "updated_name"
}

You don't need the partial = True part.

Also when there are far less excluded fields than included fields in your serializer you can do:

class Meta:
    model = Picture
    exclude = ("printed", )

Upvotes: 3

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