CODEWITHSUNDEEP
php
Haris
Haris

Reputation: 368

Reading a variable directly from file

Is it possible in PHP to, get a variable from another PHP file and assign it directly to a variable?

Eg. -

File 1 - users.php

<?php

[
    "name" => "John",
    "age" => 34
]

?>

File 2 - accounts.php

<?php

$user = get_var_from_file(users.php);

?>

get_var_from_file is the function that takes the array from users.php and assigns it directly and assigns it to $users.

Why do I want do this?

My goal here is to make the users.php file as simple as possible, because it's going to be accessed by non technical people.

Upvotes: 1

Views: 96

Answers (4)

AbraCadaver
AbraCadaver

Reputation: 78994

I would use the JSON approach, failing that I would use the CSV approach, failing that maybe parse_ini_file. However, to answer the specific format you show, just eval it:

function get_var_from_file($file) {
    $array = file_get_contents($file);
    eval("\$result = $array;");
    return $result;
}

JSON is easy, so is the INI and the CSV can be easy:

$result = array_map('str_getcsv', file($file, FILE_IGNORE_NEW_LINES));

Upvotes: 0

Jay Blanchard
Jay Blanchard

Reputation: 34406

Make the file a JSON file (remove the PHP tags) and then use file_get_contents(user.json) and then parse the JSON with json_decode(). There will be no need to reassign to other variables, just use the array identifiers from the decoding process.

Upvotes: 1

Pavel Janicek
Pavel Janicek

Reputation: 14738

You can do it by require keyword

file users.php

$users = [
  'name' => 'John',
  'age' => 34
];

file accounts.php

require('users.php');
$age = $users['age'];
echo $age;
// should return 34

Upvotes: 0

Jan Myszkier
Jan Myszkier

Reputation: 2744

simply return the variable you want to return :

<?php

return [
    "name" => "John",
    "age" => 34
]

?>

and in another file:

$users = include 'users.php';

Upvotes: 0

Related Questions